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3 years ago

Who can help me with math and english anybody that will stay and help

Advanced Placement (AP)

1 answer:

Anit [1.1K]3 years ago

8 0

Sure I’ll try to help if I know the answers :)

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While most of the geometry we have tackled in this course thus far has been presented on a flat screen, the world around you is

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At Churchland Middle School, in collaboration with our community, we ensure our students' growth and academic achievement as they develop their character in positive, safe learning environment.

These are our six core values at Churchland Middle School:

Character

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3 years ago

What are the advantages and disadvantages to shared decision-making?

inn [45]

You have others input in the situation. This can be a good or bad thing depending on colleagues or classmates mates. It depends really.

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3 years ago

Please helppp

dusya [7]

Answer:

i wish i could help but i desperately need points rn

Explanation:

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3 years ago

A child feels better after his mom gave him a spoonful of grape juice instead of Tylenol. This is known as the _____ effect.

dolphi86 [110]

Answer:the correct answer is the placebo effect

Explanation:

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3 years ago

The equilateral triangular cross sections of a solid with base an arch of y = sin(x) on

olga nikolaevna [1]

We can define the base of each equilateral section as $b(x) = \sin(x)$ since this is the distance from the x-axis to the function $y=\sin(x)$ .

An equilateral triangle's area can have a function defined solely by the base. Since all sides are equal, the height of the triangle can be found via pythagorean theorem as: $A(b)=\frac{1}{2}b\sqrt{b^2+\left (\frac{b}{2} \right)^2} = \frac{b}{2}\sqrt{\frac{5b^2}{4}}$

But we know that the base $b(x)$ is a function of x. We also can then state that Area $A(b(x))$ is also a function of x. Specifically: $A(x) = \frac{\sin(x)}{2}\sqrt{\frac{5\sin^2(x)}{4}}$ .

Then if we integrate the area function A(x) from 0 to pi, we get the total volume:

$\displaystyle \int_0^{\pi} A(x) dx = \int_0^{\pi} \frac{\sin(x)}{2}\sqrt{\frac{5\sin^2(x)}{4}} dx = \int_0^{\pi} \frac{\sqrt{5} \sin^2(x)}{4}dx$

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4 years ago