How do solve this problem. 1t-27=4t

Keith sold half of his comic books and then bought nine

Nadusha1986 [10]

Answer:

22 comic books.

Step-by-step explanation:

(20 - 9) * 2 First subtract 9 from 20

11 * 2 Multiply 11 by 2

22 is the product

3 0

3 years ago

The distance between Happyville and Giggleland is 60 miles. how far is this in kilometers?

choli [55]

Answer:

Since 1 mile = 1.60934 km 60 miles =60*1.60934 = 96.5604 km (just multiply the number of miles by 1.60934 to get kilometers.)

Step-by-step explanation:

7 0

3 years ago

A news report suggested that an adult should drink a minimum of 4 pints of water per day.

spin [16.1K]

9514 1404 393

Answer:

448

Step-by-step explanation:

(4 pt/da)×(7 da/wk)×(16 oz/pt) = 448 oz/wk

That would be 448 fluid ounces per week.

3 0

3 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

$F = \dfrac{9}{6^x}$

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

$W = \int\limits^{x_2}_{x_1} {F(x)} \, dx$

with $x_1$ and $x_2$ the initial and final displacements respectively.

From the question, $x_1 =0$ and $x_2 = 12$ .

Then

$W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx$

Evaluating the indefinite integral,

$\int\limits \dfrac{9}{6^x} \, dx =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx$

From the rules of integration,

$\int\limits a^x\, dx = \dfrac{a^x}{\ln a}$

$9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x$

Returning the limits,

$\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}$

4 0

3 years ago

A driving exam consists of 30 multiple-choice questions. Each of the 30 answers is either right or wrong. Suppose the probabili

Butoxors [25]

Answer:

a. P(x>20)=0.19

b. P(x≥6)=0.72

c. P(x≤20)=0.81

d. A and C

Step-by-step explanation:

We know that:

1) the probability that a student makes fewer than 6 mistakes is 0.28

$P(x$

2) The probaiblity that a student makes between 6 to 20 mistakes is 0.53.

$P(6\leq x\leq20)=0.53$

We will express the proabilibities in function of the information we have.

a. Probability that a student makes more than 20 mistakes.

$P(x>20)=1-P(x\leq20)=1-(P(x20)=1-(0.28+0.53)=1-0.81=0.19$

b. Probability that the student make 6 or more mistakes

$P(x\geq6)=1-P(Px$

c. Probability that a student makes 20 mistakes at most

$P(x\leq20)=P(x$

d. A and C, because A takes a event of more than 20 mistakes and C takes the event of 20 or less mistakes. Both events cover a probability of 1.

7 0

3 years ago