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jek_recluse [69]
4 years ago
10

Find coordinates of point c

Mathematics
1 answer:
BaLLatris [955]4 years ago
4 0
Ans n solution can refer in the picture

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What property is 10(5+9x) and 10(9x+5)
tatuchka [14]

Answer:

Associative property: The addition or multiplication of a several numbers is the same regardless of how the numbers are grouped. The associative property will always involve 3 or more numbers. The parenthesis groups the terms that are considered one unit.

8 0
3 years ago
Which of the following is equivalent to the sum of
barxatty [35]
Answer:I think it’s A sorry if it’s wrong.
4 0
3 years ago
What is the solution for the following system of equations?<br><br>5x + 7y = 3<br><br>2x + 3y = 1
spayn [35]
<span>A) 5x + 7y = 3
B) 2x + 3y = 1

Multiplying Equation B by -2.5
</span><span>B) -5x -7.5y = -2.5 Then adding this to Equation A)
A) 5x + 7y = 3</span>

-.5y  = .5
y = -1

Since
<span>2x + 3y = 1 then
2x -3 = 1
then x = 2

</span>
6 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
4 years ago
HELP ME PLEASE I NEED IT 40 PTS
Vikentia [17]

Answer: D

Step-by-step explanation:

10 squared is 100 and 11 squared is 121, and 111 is in between those two numbers.

8 0
4 years ago
Read 2 more answers
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