Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
This load will weigh
1.5 TONS ALTOGETHER.
So, the truck is delivering a
ton of cement blocks, and a
of bricks. To find how much this load weighs, we'd have to add the two fractions together, which proves to be quite easy, because the denominators are already the same, so we wouldn't have to change anything.
+
![\frac{5}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B8%7D%20)
=
![\frac{12}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B12%7D%7B8%7D%20)
And now, we would want to convert that fraction into a whole number, or at least a decimal, to find how many tons the truck is carrying. So we would divide. Once the work is done, here is what would happen:
12 ÷ 8 = 1.5
And there's your answer. The truck is carrying
1.5 TONS.
Câu trả lời:
0,7
Giải thích từng bước:
Xác suất để một sự kiện xảy ra = 0,3
Cho sự kiện = A
P (A) = 0,3
Xác suất mà sự kiện không xảy ra có thể thu được bằng cách sử dụng quy tắc bổ sung;
P (A ') = 1 - P (A)
Vì thế,
P (A ') = 1 - 0,3 = 0,7
Answer:
43,000: 4.3×10^4
0.0072: 7.2×10^-3
0.0000901: 9.01×10^-5
Step-by-step explanation:
scientific notation: a×10^b, where should be 0<a<10
Step 1. Count the zeros
Step 2. Look at the number left, and determine whether or not it fits in the range of [a]. If not, we divide or multiply 10 to get it fit
------------------------
43,000: 4.3×10^4 (since 43 does not fit, we divide by 10 to get it fit)
0.0072: 7.2×10^-3 (since 0.72 does not fit, we multiply 10 to get it fit)
0.0000901: 9.01×10^-5 (since 0.901 does not fit, we multiply 10 to get it fit)
Hope this helps!! :)
Please let me know if you have any question