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Arte-miy333 [17]

3 years ago

5

will ate a snack with 68.44 total calories.If the chip he ate were 39.94 calories, how many calories were in the rest of his sna

cks

1 answer:

jasenka [17]3 years ago

8 0

Subtract the total with what you have left in the chip bag. 68.44-39.94= 28.94

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Graph the system. Tell whether the system has one solution, no solution, or infinitely many solutions. y = –2x + 1 y = –2x – 3

Alchen [17]

Let's try the actual solution of the system

<span>y = –2x + 1
y = –2x – 3

Note that the slopes of the graphs of these two lines are the same: -2.

That means that the lines are parallel to one another.

Only the y-intercepts (1 and -3) are different.

Since the 2 lines never intersect, the system has no solution.

</span>

8 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

Will mark brainliest if answered correctly.

raketka [301]

Answer:

A≈126.54

Step-by-step explanation:

8 0

3 years ago

If i got a 19/25 answers right on a test what would be my test score

JulijaS [17]

76% would be your test score

6 0

3 years ago

Read 2 more answers

(-1,-1),(6,-1)<br> POINT-SLOPE FORM:<br><br> helps asap please

Aliun [14]

Answer:

y+1=0

Step-by-step explanation:

slope=-1-(-1)/6-(-1)

slope=-1+1/6+1

slope=0/7

slope=0

y-y1=m*(x-x1)

y-(-1)=0*(x-(-1))

y+1=0(x+1)

y+1=0 is correct

5 0

3 years ago