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3 years ago

HELP! What is angle 5? (PICTURE INCLUDED)

Mathematics

1 answer:

lapo4ka [179]3 years ago

6 0

Answer:

Angle 5 = 122

Step-by-step explanation:

Assume EB and AD intersect each other at point C

As this is the circle, four points A,B,D,E are all on the circle, so that we have:

+) m∠EBD = 1/2 measure of arc ED (small arc)

=> m∠EBD = 1/2 . 66 = 33 degree

=> m∠CBD = 33

+) m∠ADB = 1/2 measure of arc AB (small arc)

=>m∠ADB = 1/2 . 50 = 25 degree

=>m∠CDB = 25 degree

In the triangle CDB, we have total measure of three internal angles is 180 degree

=> Angle 5 + m∠CDB + m∠CBD = 180

=> Angle 5 + 25 + 33 = 180

=> Angle 5 = 180 -25 - 33 = 122 degree

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What is the value of 6x squared+ 4x + 8 when x=7? Please answer this I really need help!

stealth61 [152]

Let’s write it simply, that helps us solve it easier.
6x^2+4x+8
Now, insert 7 in place of x.
6(7)^2+4(7)+8
Now, multiply.
42^2+28+8
Solve for exponents.
1,764+28+8
Add.
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Hope this helps!

3 0

3 years ago

The population, p, of a town after t years is represented using the equation p=10000(1.04)^-t Which of the following is an equiv

Lisa [10]

Answer:

p=10000(26/25)t

Step-by-step explanation:

Considering that the population, p, of a town after t years is represented using the equation p=10000(1.04)^-t

The equation is equivalent to p=10000(26/25)t, because;

26/25 = 1.04

Hence; p=10000(26/25)t =p=10000(1.04)^t

3 0

3 years ago

Read 2 more answers

15 pts plz help

RoseWind [281]

Answer:

two the right then below

Step-by-step explanation:

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bx%2By%3D1%7D%20%5Catop%20%7Bx-2y%3D4%7D%7D%20%5Cright.%20%5C%5C%5Clef

brilliants [131]

Answer:

(a) x=2, y=-1

(b) x=2, y=2

(c) $\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) x=-2, y=-7

Step-by-step explanation:

Cramer's Rule

It's a predetermined sequence of steps to solve a system of equations. It's a preferred technique to be implemented in automatic digital solutions because it's easy to structure and generalize.

It uses the concept of determinants, as explained below. Suppose we have a 2x2 system of equations like:

$\displaystyle \left \{ {{ax+by=p} \atop {cx+dy=q}} \right.$

We call the determinant of the system

$\Delta=\begin{vmatrix}a &b \\c &d \end{vmatrix}$

We also define:

$\Delta_x=\begin{vmatrix}p &b \\q &d \end{vmatrix}$

And

$\Delta_y=\begin{vmatrix}a &p \\c &q \end{vmatrix}$

The solution for x and y is

$\displaystyle x=\frac{\Delta_x}{\Delta}$

$\displaystyle y=\frac{\Delta_y}{\Delta}$

(a) The system to solve is

$\displaystyle \left \{ {{x+y=1} \atop {x-2y=4}} \right.$

Calculating:

$\Delta=\begin{vmatrix}1 &1 \\1 &-2 \end{vmatrix}=-2-1=-3$

$\Delta_x=\begin{vmatrix}1 &1 \\4 &-2 \end{vmatrix}=-2-4=-6$

$\Delta_y=\begin{vmatrix}1 &1 \\1 &4 \end{vmatrix}=4-3=3$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{3}{-3}=-1$

The solution is x=2, y=-1

(b) The system to solve is

$\displaystyle \left \{ {{4x-y=6} \atop {x-y=0}} \right.$

Calculating:

$\Delta=\begin{vmatrix}4 &-1 \\1 &-1 \end{vmatrix}=-4+1=-3$

$\Delta_x=\begin{vmatrix}6 &-1 \\0 &-1 \end{vmatrix}=-6-0=-6$

$\Delta_y=\begin{vmatrix}4 &6 \\1 &0 \end{vmatrix}=0-6=-6$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-6}{-3}=2$

The solution is x=2, y=2

$\displaystyle \left \{ {{-x+2y=0} \atop {x+2y=5}} \right.$

Calculating:

$\Delta=\begin{vmatrix}-1 &2 \\1 &2 \end{vmatrix}=-2-2=-4$

$\Delta_x=\begin{vmatrix}0 &2 \\5 &2 \end{vmatrix}=0-10=-10$

$\Delta_y=\begin{vmatrix}-1 &0 \\1 &5 \end{vmatrix}=-5-0=-5$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-10}{-4}=\frac{5}{2}$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-5}{-4}=\frac{5}{4}$

The solution is

$\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) The system to solve is

$\displaystyle \left \{ {{6x-y=-5} \atop {4x-2y=6}} \right.$

Calculating:

$\Delta=\begin{vmatrix}6 &-1 \\4 &-2 \end{vmatrix}=-12+4=-8$

$\Delta_x=\begin{vmatrix}-5 &-1 \\6 &-2 \end{vmatrix}=10+6=16$

$\Delta_y=\begin{vmatrix}6 &-5 \\4 &6 \end{vmatrix}=36+20=56$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{16}{-8}=-2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{56}{-8}=-7$

The solution is x=-2, y=-7

4 0

3 years ago

What is the value of x? 6x−2(x 4)=12

jonny [76]

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Equation at the end of step 2 : 6x2 - x - 4 = 0 ((2•3x2) - x) - 4 = 0 Step 2 :Trying to factor by splitting the middle term

2.1 Factoring 6x2-x-4

The first term is, 6x2 its coefficient is 6 .
The middle term is, -x its coefficient is -1 .
The last term, "the constant", is -4 

Step-1 : Multiply the coefficient of the first term by the constant 6 • -4 = -24

Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is -1 .

-24 + 1 = -23 -12 + 2 = -10 -8 + 3 = -5 -6 + 4 = -2 -4 + 6 = 2 -3 + 8 = 5 -2 + 12 = 10 -1 + 24 = 23

Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored

Equation at the end of step 2 : 6x2 - x - 4 = 0

3 0

3 years ago