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Shalnov [3]
3 years ago
5

A toy has various shaped objects that a child is supposed to push through matching holes. The area of the square hole is 5 cm2.

The area of the circular face of the round peg is 5 cm2. Will the round peg fit through the square hole? Use r = 3.14. Round to the nearest hundredth as needed. Explain
Mathematics
1 answer:
Papessa [141]3 years ago
5 0

To answer this, let's first describe the two areas and obtain the pertinent dimensions from them.

The area of the square hole is 5 cm^2.  Since A = s^2, where s is the length of a side of the square, s = +√5 in this situation.  +√5 is approx. 2.24 cm.

The area of the round peg is 5 cm^2 also, but the area is calculated using a different formula:  A = πr^2, where r is the radius of the circle.  Solving for r^2, we get:

                 r^2 = A/π.   Here, r^2 = (5 cm^2)/π = 5π, so that:

r = +√(5π).  This is approx. 3.96 cm, and so the diameter is twice that, or 7.93 cm.

So there's plenty of room for the round peg to enter the square hole, but not the other way around!

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Airida [17]

Answer:

r = - \frac{1}{3}

Step-by-step explanation:

The n th term of a GP is

a_{n} = a₁ r^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 18 and a₆ = - \frac{2}{27} , then

18 r^{5} = - \frac{2}{27} ( divide both sides by 18 )

r^{5} = - \frac{1}{243} ( take the fifth root of both sides )

r = \sqrt[5]{-\frac{1}{243} } = - \frac{1}{3}

4 0
2 years ago
Find the distance between the points given.
Maru [420]

Use the distance formula

d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2

Input corresponding numbers

d = \sqrt {\left( {2- 6} \right)^2 + \left( {5-8} \right)^2

Solve

d = \sqrt {\left( {-4} \right)^2 + \left( {-3} \right)^2

\sqrt{16 + 9}

\sqrt{25} = 5\\\\ d=5

So, the distance between the points given is 5

4 0
3 years ago
You work at an ice-cream shop. One of your jobs is to order new ice-cream cones. You pick the cone that is 5 inches high and has
Taya2010 [7]
We have that
the Volume of cone=(1/3)*B*h
B=the area of the base
h= the height of the cone
D=3.5 in-----------------> r=D/2=1.75 in
h=5 in
B=pi*r²---------> 3.14*1.75²=9.616 in²
V=(1/3)*9.616*5=48.08 in³--------> 48 in³

the answer is 48 in³
5 0
3 years ago
Read 2 more answers
A ratio compares the relative sizes of ______ quantities .​
Andre45 [30]

Answer:

two

Step-by-step explanation:

A ratio compares the relative sizes of two quantities .​

4 0
3 years ago
A baseball team played 130 games in a season. If it won sixteen more games
egoroff_w [7]

Answer:

The team has 92 wins and 38 losses.

Step-by-step explanation:

In a season 130 games are played by a baseball team.

Let us assume that the team wins x games and losses y games.

Therefore, we can write, x + y=130....... (1)

It is given that if the team won sixteen more games twice as many games as it lost.

So, we can conclude that x =2y+16 ......(2)

Hence, solving equations (1) and (2) we get, (2y+16) + y =130

⇒ 3y = 114

⇒ y =38

And from equation (2), x = 2×38 + 16 = 92

Therefore, the team has 92 wins and 38 losses. (Answer)

4 0
3 years ago
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