Answer:
100 lightbulbs
Step-by-step explanation:
Basically find the percentage of lightbulbs that are bad. 5/136. So about 3. 6 percent. I'm going to use a more exact form of this percent for my calculations though. Now use the decimal for of this (0.036....) and multiply it by 2720. Using my exact decimal, the answer just so happened to be exactly 100. So there will be 100 defective lightbulbs per day. (Teachers are a stickler for units, so don't forget them if it's for a teacher)
Hope this helps!
Answer is D, 2(4a + 7.)
A is equivalent to 4a + 24.
B is equivalent to 16a + 40.
C is equivalent to 8a + 32.
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Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
Answer:
The estimate of a population proportion is approximately 541.
Step-by-step explanation:
We can solve the the problem by using the formula for minimum sample needed for interval estimate of a population proportion which is given by the formula
n = pq ((Z/2) / E)^2
As, p is not defined so we use the standard p and q which is 0.5 and 0.5.
The reason for this is we have to choose form 0.1 to 0.9 both values of p and q, we will find the maximum value of pq occurs when they both are 0.5.
Next, we will find the value of (Z/2) by looking at the Z-table, we will find that at 98% confidence (Z/2) = 2.326. Now we start substituting the values in the above formula
n = (0.5)×(0.5) × (2.326/0.05)^2
n = 541.027
n ≅ 541.
Answer:
a. 12s + 19j - 3
36 + 28 - 3 = 61
b.
Shirt (per unit cost):
Before Discount: $12
After Discount: $12 - $3 = $9
Jeans (pair cost):
Before Discount: $19
After Discount: $19 - $3 = $16
(12-3)s + (19-3)j
27 + 32 = $59
