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3 years ago

Joe divided a candy bar into 8 equal pieces what fraction show how much candy each of the four children got

Mathematics

2 answers:

Elza [17]3 years ago

7 0

The fraction each of the four children got is 2^8

amm18123 years ago

7 0

The answer is 2/8 each child would get 2 pieces of candy

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I forgot how to do this. Can anyone help me please

Svetach [21]

Answer:

Step-by-step explanation:

180 since it is supplementary

then minus 100 which is 80 then minus 12 which is 68 then half that which is 34

7 0

2 years ago

Read 2 more answers

At a lunch stand, each hamburger has 50 more calories than each order of fries. If 2 hamburgers and 3 orders of fries have a tot

Vedmedyk [2.9K]

Answer: 960 calories

Step-by-step explanation:

Given

Each hamburger has 50 more calories than each order of fries

Suppose each order of fries has $x$ calories

so, hamburger has $x+50$ calories

There are total of 1700 calories available. Thus, we can write

$\Rightarrow 2(x+50)+3x=1700\\\Rightarrow 2x+3x=1700-100\\\Rightarrow 5x=1600\\\Rightarrow x=320$

So, each order of fries has $320$ calories

For 3 orders, it is $320\times 3=960$ calories

7 0

3 years ago

Holly had 5,000 in her bank account she withdrew 800 to buy a new bike what is the percent decrease in the balance of her accoun

Anika [276]

800/5000*100=16%
Holly's account decreases on 16 percents

6 0

3 years ago

The graph shows one of the linear equations for a system of equations. Which equation represents the second linear equation for

erastova [34]

Answer:

C) 2/3x + 3y = 3

Step-by-step explanation:

The attached graph shows only choice C intersects the desired point.

Essentially, the given graph is irrelevant. What you want to know is which equation has (3/4, 5/6) as a solution.

There are at least a couple of ways you can figure this out:

try the given point in the equations to see which one works
examine the features of the given equations to see which might work

If we consider the second approach, we realize all of the equations have negative y-intercepts except choice C*. For an equation with a negative y-intercept to be the solution, the x-intercept must be less than 3/4. That is not the case for any of choices A, B, or D, leaving only choice C as a viable possibility.

We can check to see if the given point satisfies choice C. Filling in for x and y, we get ...

(2/3)(3/4) + 3(5/6) = 2/4 +5/2 = 3 . . . . . . the point is on this line

_____

In the attached graph, choice C is the black line.

_____

* For an equation of the form ax+by=c, the y-intercept is c/b and the x-intercept is c/a. The sign of the quotient can be figured from the signs of a, b, and c without doing any division.

_____

<em>Comment on intercepts</em>

Considering the signs and values of the x- and y-intercepts can tell you a lot about the solution to a system of equations. They tell you where the line segment between the axes lies, and they can give you a clue as to the location (quadrant) of the intersection point of two lines. Often, the intercepts are all you need to create a useful graph of an equation.