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nevsk [136]
3 years ago
6

Easy 6th-grade math question

Mathematics
2 answers:
schepotkina [342]3 years ago
8 0

Answer:

a+5

Step-by-step explanation:

Im in 12th grade this stuff is easy

Vlada [557]3 years ago
4 0

Answer:

the answer is a+5

Step-by-step explanation:

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1. (2x+5)+(3x-2)= <br> 2. (3x-2)-(2x+5)=<br> 3. (2x+5)-(3x-2=
DIA [1.3K]

Answer:

  1. 5x+3
  2. x -7
  3. -x +7

Step-by-step explanation:

Combine like terms. The associative and commutative properties of addition apply, as does the distributive property.

__

1. (2x+5)+(3x-2) = (2x +3x) +(5 -2) = 5x +3

__

2. (3x-2)-(2x+5) = 3x -2 -2x -5 = (3x -2x) +(-2 -5) = x -7

__

3. (2x+5)-(3x-2) = 2x +5 -3x +2 = (2x -3x) +(5 +2) = -x +7

_____

<em>Additional comment</em>

Note that swapping the order of operands in a subtraction problem (problems 2 and 3) will cause the sign of the result to reverse.

6 0
3 years ago
Help Me!
puteri [66]

Answer:

<u>Given:</u>

  • DC ║ AB
  • CM = MB as M is midpoint of BC

i) <u>Since DN and BC are transversals, we have:</u>

  • ∠DCM ≅ ∠NBM and
  • ∠CDM ≅ ∠BNM as alternate interior angles

<u>As two angles and one side is congruent, the triangles are also congruent:</u>

  • ΔDCM ≅ ΔNBM (according to AAC postulate)

So their areas are same.

ii)

<u>The quadrilateral has area of:</u>

  • A(ADCB) = A(ADMB) + A(DCM)

<u>And the triangle has area of:</u>

  • A(ADN) = A(ADMB) + A(NBM)

Since the areas of triangles DCM and NBM are same, the quadrilateral ADCB has same area as triangle ADN.

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The last statement is true based on the information in the table

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