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2 years ago

Easy 6th-grade math question

Mathematics

2 answers:

schepotkina [342]2 years ago

8 0

Answer:

a+5

Step-by-step explanation:

Im in 12th grade this stuff is easy

Vlada [557]2 years ago

4 0

Answer:

the answer is a+5

Step-by-step explanation:

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Luke buys a certain brand of cereal that costs $11 per box. Luke changes to a super-saving brand of the same size. The equation

marishachu [46]

Y = 9x means each box of the new brand is $9.

So the old brand is $2 per box more. I know you 

can do part B now!
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2 years ago

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Please help i need this done soon!

Kamila [148]

Answer:

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Step-by-step explanation:

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3 years ago

Plz help. Write the slope intercept form of the equation

Fudgin [204]

Answer:

2nd option is correct

Step-by-step explanation:

x +2y=14

2y = -x + 14

y= -x/2 +7

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2 years ago

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Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

7 0

2 years ago

Write the following as an inequality 6 is greater than or equal to x and -2 is less than or equal to x

kipiarov [429]

Answer:

-2 ≤ x ≤ 6

Step-by-step explanation:

The first is ...

6 ≥ x

and it can also be written as ...

x ≤ 6

The second is

-2 ≤ x

The two inequalities can be combined into one compound inequality:

-2 ≤ x ≤ 6

_____

Comment on this answer

I prefer the answer in this form because it puts the parts of the expression in the same order that they appear on a number line. It can also be written as ...

6 ≥ x ≥ -2

7 0

3 years ago