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Alex
3 years ago
12

Which graph represents the solution to the system of inequalities? x + y ≤ 4 y – x ≥ 1

Mathematics
1 answer:
frosja888 [35]3 years ago
5 0

Given inequalities are

x+y\le4 and

y-x\ge1

Now we will graph both inequalities to get the common region which represents solution.

<u>Work for x+y\le4 </u>

first we graph the line x+y=4 then shade the graph for inequality symbol \le

we can plug any random number for x and find y-value to get points

lets plug x=0 then we get:

x+y=4

0+y=4

y=4

so the point is (0,4)

Similarly we can find more point like (4,0).

Now graph both points and join both points by straight line.

Now we find direction of shading.

pick any test point which is not on that line x+y=4 say (0,0)

and plug it into orinal inequality x+y\le4

0+0\le4

0\le4

which is true.

True means shade in direction of test point. Otherwise we shade in opposite direction.

We will repeat same process for other inequality to graph that.

Hence final graph for the answer will be as shown in attached image.

Triangular region ABC is final answer.

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8 0
3 years ago
Match the following rational expressions to their rewritten forms.
Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}

And the rewritten forms:

(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}

So, correct option is 3.

(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}

So, correct option is 1.

(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}

So, correct option is 2.

(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}

So, correct option is 4.

The answer is also attached in the answer area.

7 0
3 years ago
Write a problem to fit this equation 2K + 5 =29
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2K + 5 = 29

(2 x K) + 5 = 29

29 - 5 = 24

24 divided by 2 = 12 (This is K)

K = 12

(2 x 12) + 5 = 29  


24 + 5 = 29

6 0
3 years ago
in a trivia game Joshua gets the score of -4 and the first round and it got five in the second round what is his total score aft
tankabanditka [31]
Joshua’s total score is 1 cuz -4 + 5 = 1
4 0
3 years ago
vRichard has a red card (R) and a black card (B). He picks a card randomly from the pair and then rolls a six-sided die. The sam
Alik [6]

The Sample space for three cards is

S=\left\{\left(B,1\right),\left(R,1\right),\left(G,1\right),\left(B,2\right),\left(R,2\right),\left(G,2\right),\left(B,3\right),\left(R,3\right),\left(G,3\right),\left(B,4\right),\left(R,4\right),\left(G,4\right)\left(B,5\right),\left(R,5\right),\left(G,5\right),\left(B,6\right),\left(R,6\right),\left(G,6\right) \right \}

There are two cards red(R) and black(B) and a six-sided die.

The event is one card is picked randomly and then rolls the die.

So, the Sample space is as follows.

S=\left\{\left(B,1\right),\left(R,1\right),\left(B,2\right),\left(R,2\right),\left(B,3\right),\left(R,3\right),\left(B,4\right),\left(R,4\right),\left(B,5\right),\left(R,5\right),\left(B,6\right),\left(R,6\right) \right \}

<h3>Find Sample space if there are three cards.</h3>

Consider there were three cards red(R), black(B) and green(G) a six-sided die.

The event is one card is picked randomly and then rolls the die.

So, the sample space will be as follows,

S=\left\{\left(B,1\right),\left(R,1\right),\left(G,1\right),\left(B,2\right),\left(R,2\right),\left(G,2\right),\left(B,3\right),\left(R,3\right),\left(G,3\right),\left(B,4\right),\left(R,4\right),\left(G,4\right)\left(B,5\right),\left(R,5\right),\left(G,5\right)\left(B,6\right),\left(R,6\right),\left(G,6\right) \right \}.

Learn more about sample space here :-

brainly.com/question/24273864

#SPJ1

7 0
2 years ago
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