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3 years ago

Write 900.000+80.000+500+7 in standard from.

Mathematics

2 answers:

Bas_tet [7]3 years ago

3 0

980,507 i believe... maybe

Savatey [412]3 years ago

3 0

980,507 is the standard form

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What is the surface area? 10 cm 7 cm 3 cm square centimeters

alexandr1967 [171]

Answer:

242cm^2

Step-by-step explanation:

The formula for surface area of a rectangular(assuming that's what you have) is Perimeter of the Base(height) + 2(Area of the Base)

Or you could add up all the sides, or use this formula

SA=2(length*width)+2(length*height)+2(height*width)

2×(10×7 + 10×3 + 7×3)

helpful links:

https://www.khanacademy.org/math/ basic-geo/basic-geo-volume-sa/basic-geometry-surface-area/v/surface-area-of-a-box

http://www.math.com/tables/geometry/surfareas.htm

https://www.basic-mathematics.com/surface-area-formula.html

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3 years ago

If a straight angel is bisected, what type of angels are the resulting angels

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Factor the trinomial x^2 + 6x - 27

krek1111 [17]

If you factor the trinomial using the AC method the answer would be

(x-3)(x+9)

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Jacob is visiting Argentina, and he hears a warning that the temperature may drop as low as -12.4°C. How cold is that in °F, to

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The answer would be C

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Suppose that, for a particular social networking company, the annual revenue from rich media advertisements, in millions of doll

Juli2301 [7.4K]

Answer:

a. Revenue of the company at the beginning of 2010 is 75 million dollar (loss)

b. Rate at which the revenue changing in the year 2010 is 76 million dollar per year ( decreasing)

Step-by-step explanation:

For part a,

Given that x is the number of years at the beginning of 2007.

Therefore, $x=0$ for year 2007.

Hence at the year 2010 value of x will be $x=3$ .

Substitute the value of x=3 in R(x),

$R\left(x\right)=-x^{4}+8x^{3}-38x^{2}+44x$

$R\left(x\right)=-\left(81\right)+8\left(27\right)-38\left(9\right)+132$

$R\left(x\right)=-81+216-342+132$

$R\left(x\right)=-75$

Negative sign indicates that there is loss of revenue at the start of the year 2010

Therefore, there is loss of revenue at the beginning of 2010 which is 75 million dollar.

For part b,

To calculate rate, differentiate the given function with respect to x.

$\dfrac{d}{dx}R\left(x\right)=\dfrac{d}{dx}\left (-\left(x\right)^{4}+8\left(x\right)^{3}-38\left(x\right)^{2}+44\left(x\right)\right)$

Applying sum and difference rule of derivative,

$\dfrac{d}{dx}R\left(x\right)=-\dfrac{d}{dx}\left(x^4\right)+\dfrac{d}{dx}\left(8x^3\right)-\dfrac{d}{dx}\left(38x^2\right)+\dfrac{d}{dx}\left(44x\right)$

Applying constant multiple rule of derivative,

$\dfrac{d}{dx}R\left(x\right)=-\dfrac{d}{dx}\left(x^4\right)+8\dfrac{d}{dx}\left(x^3\right)-38\dfrac{d}{dx}\left(x^2\right)+44\dfrac{d}{dx}\left(x\right)$

Applying power rule of derivative,

$\dfrac{d}{dx}R\left(x\right)=-\left(4x^{4-1}\right)+8\left(3x^{3-1}\right)-38\left(2x^{2-1}\right)+44\left(1x^{1-1}\right)$

$\dfrac{d}{dx}R\left(x\right)=-4\left(x^{3}\right)+8\left(3x^{2}\right)-38\left(2x^{1}\right)+44$

$\dfrac{d}{dx}R\left(x\right)=-4x^3+24x^2-76x+44$

Substituting the value x=3,

$\dfrac{d}{dx}R\left(x\right)=-4\left(3\right)^3+24\left(3\right)^2-76\left(3\right)+44$

$\dfrac{d}{dx}R\left(x\right)=-4\left(27\right)+24\left(9\right)-76\left(3\right)+44$

$\dfrac{d}{dx}R\left(x\right)=-108+216-228+44$

$\dfrac{d}{dx}R\left(x\right)=-76$

Negative sign indicates that rate is decreasing.

Rate at which the revenue is changing in the year 2010 is 76 million dollar per year.

8 0

3 years ago