Assumin we solving for the intersection or solution
elimination, ya
eliminate y's
multiply firs equation by 2 and add to 2nd
we get
6x+2y=16
<u>-x-2y=-10 +</u>
5x+0y=6
5x=6
divide both sides by 5
x=6/5
sub back
-x-2y=-10
-6/5-2y=-10
times both sides by 5
-6-10y=-50
add 6 to both sides
-10y=-44
divide both sides by -10
y=44/10
y=22/5
(x,y)
or
(1.2,4.4)
Answer:
If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent. ASA
Step-by-step explanation:
Answer:
11×20
Step-by-step explanation:
15 + 5 = 20
Using the Law of Sines (sinA/a=sinB/b=sinC/c) and the fact that all triangles have a sum of 180° for their angles.
The third angle is C is 180-53-17=110°
27/sin53=b/sin17=c/sin110
b=27sin17/sin53, c=27sin110/sin53
And the perimeter is a+b+c so
p=27+27sin17/sin53+27sin110/sin53 units
p≈68.65 units (to nearest hundredth of a unit)
The answer is A.
The way you know this is by graphing the first function.
The second function is in a different format, so you just have to isolate Y.
-1/3x + y = -1
y= 1/3x -1 OR y= -1 + 1/3x
both of the functions have the same slope, but different y-intercepts. therefore, they'll never touch. making them infinite solutions.
it's also A because both of the slopes are positive, the slopes in graph D are negative.
So, the answer is A.
Hope this helps! xx
