Q. How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
Solution:
Here we are given with the sides of the triangle as 5m, 16m and 5.
As the Triangle inequality we know that
The sum of the length of the two sides should be greater than the length of the third side. But this inequality fails here.
Hence no triangle can be made.
So the correct option is None.
Q.How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?
Solution:
Here we are given with the sides of the triangle as 6m, 2m and 7m.
As the Triangle inequality we know that
The sum of the length of the two sides should be greater than the length of the third side. The given values follows the triangle inequality.
Hence one triangle can be formed.
So the correct option is one.
Answer:
-6d^2 + 12d - 3
Step-by-step explanation:
use PEMDAS
parentheses
exponents
multiplication
division
addition
subtraction
use that order to solve problems like that.
Answer:
a. 1620-x^2
b. x=810
c. Maximum value revenue=$656,100
Step-by-step explanation:
(a) Total revenue from sale of x thousand candy bars
P(x)=162 - x/10
Price of a candy bar=p(x)/100 in dollars
1000 candy bars will be sold for
=1000×p(x)/100
=10*p(x)
x thousand candy bars will be
Revenue=price × quantity
=10p(x)*x
=10(162-x/10) * x
=10( 1620-x/10) * x
=1620-x * x
=1620x-x^2
R(x)=1620x-x^2
(b) Value of x that leads to maximum revenue
R(x)=1620x-x^2
R'(x)=1620-2x
If R'(x)=0
Then,
1620-2x=0
1620=2x
Divide both sides by 2
810=x
x=810
(C) find the maximum revenue
R(x)=1620x-x^2
R(810)=1620x-x^2
=1620(810)-810^2
=1,312,200-656,100
=$656,100
C = 5(F-32)/9 Multiply each side by 9
9C = 5(F-32) Distribute
9C = 5F - 160 Add 160 to each side
9C + 160 = 5F Divide each side by 5
9/5C + 32 = F
Answer:
4L-12
Step-by-step explanation:
let's assume the length = L
then the width of the rectangle is L - 6
perimeter = 2× (a+b)
where "a" and "b" are the length and the width of the rectangle.
so perimeter = 2× (L + L - 6)
2 × ( 2L - 6)
4L - 12
