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lyudmila [28]
3 years ago
13

A basketball player scored 24 times during one game. She scored a total of 41 points, two for each two-point shots and one for e

ach free-throw how many to point shots did she make? How many free throws?
Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

<em>Number of points shoot, x=17</em>

<em>Number of </em><em>free</em><em> </em><em>shoot</em><em>,</em><em> </em><em>y</em><em>=</em><em>7</em>

Step-by-step explanation:

Let us consider,

point shoot as x

free shoot as y.

Question say " A basketball player scored 24 times during one game "

Therefore, Number of point shoot + Number of free shoot = 24

Numerically we get,

x+y=24

Now, Free shoot gives one point and point shoot gives two points.

She scored total of 41 points.

2x+y=41

we get two equations

x+y=24

2x+y=41

By solving above linear equations...

we can write, y=24-x

replacing y value in 2x+y=41

2x+24-x=41

<em>x=17</em>

To find value of y, replace x vaule in any equation

say, x+y=24

17+y=24

<em>y=7</em>

Thus, x=17 and y=7

Number of points shoot, x=17

Number of free shoot, y=7

julsineya [31]3 years ago
6 0

Answer:

x=17

Step-by-step explanation:

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Find the zeros of the following polynomial functions, with their multiplicities. (a) f(x)= (x +1)(x − 1)(x² +1) (b) g(x) = (x −
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Answer:

a) zeros of the function are x = 1 and, x = -1

b) zeros of the function are x = 2 and, x = 4

c) zeros of the function are x = \frac{3}{2}

d) zeros of the function are x = \frac{-4}{3}  and, x = 17

Step-by-step explanation:

Zeros of the function are the values of the variable that will lead to the result of the equation being zero.

Thus,

a) f(x)= (x +1)(x − 1)(x² +1)

now,

for the (x +1)(x − 1)(x² +1) = 0

the condition that must be followed is

(x +1) = 0 ..........(1)

or

(x − 1) = 0 ..........(2)

or

(x² +1) = 0 ...........(3)

considering the equation 1, we have

(x +1) = 0

or

x = -1

for

(x − 1) = 0

x = 1

and,

for (x² +1) = 0

or

x² = -1

or

x = √(-1)         (neglected as it is a imaginary root)

Thus,

zeros of the function are x = 1 and, x = -1

b) g(x) = (x − 4)³(x − 2)⁸

now,

for the (x − 4)³(x − 2)⁸ = 0

the condition that must be followed is

(x − 4)³ = 0 ..........(1)

or

(x − 2)⁸ = 0 ..........(2)

considering the equation 1, we have

(x − 4)³ = 0

or

x -4 = 0

or

x = 4

and,

for (x − 2)⁸ = 0

or

x - 2 = 0

or

x = 2        

Thus,

zeros of the function are x = 2 and, x = 4

c) h(x) = (2x − 3)⁵

now,

for the (2x − 3)⁵ = 0

the condition that must be followed is

(2x − 3)⁵ = 0

or

2x - 3 = 0

or

2x = 3

or

x = \frac{3}{2}

Thus,

zeros of the function are x = \frac{3}{2}

d)   k(x) =(3x +4)¹⁰⁰(x − 17)⁴

now,

for the (3x +4)¹⁰⁰(x − 17)⁴ = 0

the condition that must be followed is

(3x +4)¹⁰⁰ = 0 ..........(1)

or

(x − 17)⁴ = 0 ..........(2)

considering the equation 1, we have

(3x +4)¹⁰⁰ = 0

or

(3x +4) = 0

or

3x = -4

or

x = \frac{-4}{3}

and,

for (x − 17)⁴ = 0

or

x - 17 = 0

or

x = 17        

Thus,

zeros of the function are x = \frac{-4}{3}  and, x = 17

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