All categories

3 years ago

Can someone help me with this please? Thanks! Show your work :)

Mathematics

1 answer:

Alexandra [31]3 years ago

6 0

I got 1/81. because u spun the spinner twice i multiplied the regions you are allowed to get by 2 which makes your denominator 18 then you can get the numbers 3 and 6 twice since the spinner is used twice then multiplied them together. so it would be 2/18 x 2/18 = 4/324 which equals 1/81

You might be interested in

I need help to start this problem. Can some help? The problem is 5k+6-k≥-14

lys-0071 [83]

4k+6 is greater or equal to -14
4k is greater or equal to -20
k is greater or equal to -5 <-- answer

6 0

3 years ago

Read 2 more answers

EASY POINTS (attached)

solong [7]

Answer for the first one - it's complicated, but that maths is correct

I kind of cheated and did it a different way than they'd expect. By doing 24 squared, that gives you 576.

since both angles are 45 degrees, then the sides are equal lengths. Therefore x squared times 2 = 576.

Because of this, x squared = 576 divided by 2, which equals 288.
Therefore the square root of 288 = 12 square root 2

5 0

3 years ago

Read 2 more answers

6(v+2) - 7v = 6 + 5v

slava [35]

Answer:

v = 1

Step-by-step explanation:

6(v+2) - 7v = 6 + 5v

open Parentheses

6*v=6v

6*2=12

New equation:

6v + 12 - 7v = 6 + 5v

simplify

12 - v = 6 + 5v

match like terms

6 = 6v

solve

1 = v

4 0

3 years ago

Read 2 more answers

2. After the relay race, Larry, Curly, and Moe went to the

jarptica [38.1K]

Using proportions, it is found that each of the 6 people got $0.5.

<h3>Proportions:</h3>

This question is solved by proportions, using a rule of three.

$3.00 is shared between 6 people, which are Larry, Curly, Moe, Alvin, Simon and Theodore. How much did each people(1 person) get?

The rule of three is:

$3.00 - 6 people

$x - 1 person

Applying cross multiplication:

$6x = 3$

$x = \frac{3}{6}$

$x = 0.5$

Each of the 6 people got $0.5.

To learn more about proportions, you can take a look at brainly.com/question/24372153

7 0

2 years ago

An instructor in a college class recently gave an exam that was worth a total of 100 points. The instructor inadvertently made t

solniwko [45]

Answer:

B) Method 2 will increase the standard deviation of the students' scores.

Step-by-step explanation:

Given that an instructor in a college class recently gave an exam that was worth a total of 100 points.

The average score for his students was 43 and the standard deviation of the scores was 5 points.

And now he is considering two different strategies for rescaling the exam results of which:

Method 1 = Add 17 points to everyone's score.

Method 2 = Multiply everyone's score by 1.7 .

And we have to check what will be the impact of these methods on the standard deviation of the students' scores.

For this let us consider a simple example to understand this:

Firstly, Formula for calculating Standard Deviation = $\sqrt{\frac{\sum (X-Xbar)^{2}}{n-1}}$

Suppose,

X X - Xbar $(X - Xbar)^{2}$

3 3 - 6 = -3 -3 * -3 = 9

5 5 - 6 = -1 -1 * -1 = 1

10 10 - 6 = 4 4 * 4 = 16

Mean of above data, Xbar = $\frac{3+ 5+10}{3}$ = 6

Standard Deviation of data = $\sqrt{\frac{26}{3-1} }$ = 3.6055

Now let us suppose that we multiply each value of above data with 2 so the new data will be:

X X - Xbar $(X - Xbar)^{2}$

3*2 = 6 6 - 12 = -6 -6 * -6 = 36

5*2 = 10 10 - 12 = -2 -2 * -2 = 4

10*2 =20 20 - 12 = 8 8 * 8 = 64

Mean of new data, Xbar = $\frac{6+ 10+20}{3}$ = 12

Standard Deviation of new data = $\sqrt{\frac{104}{3-1} }$ = 7.2111

Hence, we see that when we multiply any value to the data the standard deviation will increase and in other words it will multiplied by that value which value we multiplied with each data value i.e. when we multiply each data value with 2 the standard deviation also get multiplied by as

3.6055 * 2 = 7.2111

Therefore option B is correct that Method 2 will increase the standard deviation of the students' scores.

And on the other hand Similarly by adding any constant to the data the Standard Deviation will remain same. Therefore Method 1 will have no impact on standard deviation of the students' scores.

8 0

3 years ago