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madam [21]
3 years ago
7

adult tickets to a basketball game cost $5. student tickets cost $1. A total of $2,459 was collected on the sale of 1,119 ticket

s. how many of these type of tickets was sold?​
Mathematics
1 answer:
MakcuM [25]3 years ago
6 0

335 adult tickets and 784 student tickets were sold.

Step-by-step explanation:

Given,

Price of adult ticket = $5

Price of student ticket = $1

Suppose,

Adults = x

Students = y

According to price;

5x + 1y = 2459 Eqn 1

and tickets sold are;

x + y = 1119 Eqn 2

Subtracting\ Eqn\ 2\ from\ Eqn\ 1;\\(5x+y)-(x+y)=2459-1119\\5x+y-x-y=1340\\4x=1340\\Dividing\ both\ sides\ by\ 4\\\frac{4x}{4}=\frac{1340}{4}\\x=335\\

Putting value of x in Eqn 2;

335+y=1119\\Subtracting\ 335\ from\ both\ sides\\335-335+y=1119-335\\y=784

335 adult tickets and 784 student tickets were sold.

Keywords: Linear equations, subtraction.

Learn more about linear equations at:

  • brainly.com/question/2160689
  • brainly.com/question/2166248

#LearnwithBrainly

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expeople1 [14]
Given:
- Bought n items of product A at 1/5 rs each
- bought n items of product B at 1/4 rs each
He mixed the two items and sold each at 2/9 rs each.
He lost 3 rs in the above batch of articles.

Solution:
revenue = 2n* (2/9) rs = 4n/9 rs
cost = n/5+n/4 rs = n(1/5+1/4)
Profit = revenue-cost = 4n/9-n(1/5+1/4) = -3 rs

Solve for n
4n/9-n(1/5+1/4) = -3 
factor out n
n(4/9-1/5-1/4)=-3
n(80-36-45)/180=-3
-n/180=-3
n=3*180=540

Total number of products bought
= n+n = 540+540 = 1080
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