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enot [183]
3 years ago
13

Factor the expression. 35g^2 – 2gh – 24h^2

Mathematics
1 answer:
stiks02 [169]3 years ago
3 0

Option C: (7 g-6 h)(5 g+4 h) is the correct answer.

Explanation:

The given expression is 35 g^{2}-2 g h-24 h^{2}

We need to determine the factor of the expression.

Now, let us break the given expression into two groups.

Hence, we get,

35 g^{2}+28 g h-30 g h-24 h^{2}

Simplifying, we get,

\left(35 g^{2}+28 g h\right)+\left(-30 g h-24 h^{2}\right)

Let us factor out 7g from the term \left(35 g^{2}+28 g h\right)

Hence, we have,

7 g(5 g+4 h)+\left(-30 g h-24 h^{2}\right)

Similarly, let us factor out -6h from the term \left(-30 g h-24 h^{2}\right)

Thus, we have,

7 g(5 g+4 h)-6 h(5 g+4 h)

Now, we shall factor out the term 5g+4h , we get,

(7 g-6 h)(5 g+4 h)

Thus, the factorization of the given expression is (7 g-6 h)(5 g+4 h)

Therefore, Option C is the correct answer.

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Answer:

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Step-by-step explanation: The bigger triangle is 6 times bigger than the smaller one.

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3 years ago
(4x-9)(2x^2+2x+1) (4x−9)(2x 2 +2x+1)
tia_tia [17]

Answer:

(4x-9)^2*(2x^2+2x+1)^2

Step-by-step explanation:

(((4x-9)•(((2•(x2))+2x)+1))•(4x-9))•((2x2+2x)+1)

]  (((4x-9)•((2x2+2x)+1))•(4x-9))•(2x2+2x+1)

Trying to factor by splitting the middle term

Factoring  2x2+2x+1

The first term is,  2x2  its coefficient is  2 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  +1

Step-1 : Multiply the coefficient of the first term by the constant   2 • 1 = 2

Step-2 : Find two factors of  2  whose sum equals the coefficient of the middle term, which is   2 .

     -2    +    -1    =    -3

     -1    +    -2    =    -3

     1    +    2    =    3

     2    +    1    =    3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

 ((4x-9)•(2x2+2x+1)•(4x-9))•(2x2+2x+1)

Multiplying Exponential Expressions:

4.1    Multiply  (4x-9)  by  (4x-9)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (4x-9)  and the exponents are :

         1 , as  (4x-9)  is the same number as  (4x-9)1

and   1 , as  (4x-9)  is the same number as  (4x-9)1

The product is therefore,  (4x-9)(1+1) = (4x-9)2

Trying to factor by splitting the middle term

5.1     Factoring  2x2+2x+1

The first term is,  2x2  its coefficient is  2 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  +1

Step-1 : Multiply the coefficient of the first term by the constant   2 • 1 = 2

Step-2 : Find two factors of  2  whose sum equals the coefficient of the middle term, which is   2 .

     -2    +    -1    =    -3

     -1    +    -2    =    -3

     1    +    2    =    3

     2    +    1    =    3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Multiplying Exponential Expressions:

5.2    Multiply  (2x2+2x+1)  by  (2x2+2x+1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (2x2+2x+1)  and the exponents are :

      1 , as  (2x2+2x+1)  is the same number as  (2x2+2x+1)1

and   1 , as  (2x2+2x+1)  is the same number as  (2x2+2x+1)1

The product is therefore,  (2x2+2x+1)(1+1) = (2x2+2x+1)2

Final result :

 (4x - 9)2 • (2x2 + 2x + 1)2

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Answer:

the highest common factor of the polynomial is (x + 2) (x - 3)

Step-by-step explanation:

The computation of the highest common factor of the polynomial is as follows:

According to the question, the following equation is given

'x^2 - x - 6

Now do the factorization

x^2 -3x + 2x - 6

x(x - 3) +2 (x - 3)

(x + 2) (x - 3)

hence, the highest common factor of the polynomial is (x + 2) (x - 3)

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