Below is the solution:
There are two equations to be solved here. The first one we assign variables to the home runs Peter hits, P, and Alice hits, A. P=2*(A-6) The second equation is the sum of both players home runs.P + A = 18Solving for P yieldsP=18-A We substitute the solution for P into the first equation and solve for A.(18-A) = 2*(A-6)18 - A = 2A - 123A = 30A = 10 Now that A is known, we can plug it into either equations for P to find how many home runs Peter hitsP=18 - (10) = 8orP=2((10)-4) = 8
Answer:

We can divide both sides by 20 and we got:

Now we can appply natural log on both sides and we got:

Now we can divide both sides of the equation by 10 and we got:

So then the aproximate value of k is 0.30986 and rounded would be 0.31
Step-by-step explanation:
We have the following two expression:


We know that the two populations were equal 10 years after the start of the study, so then we can create the following equation:

We can divide both sides by 20 and we got:

Now we can appply natural log on both sides and we got:

Now we can divide both sides of the equation by 10 and we got:

So then the aproximate value of k is 0.30986 and rounded would be 0.31
9514 1404 393
Answer:
Dawn has $1670 in account 1 and $1570 in account 2.
Step-by-step explanation:
Dawn can multiply the second equation by 8 and add 7 times the first equation.
8(3/8A +7/8B) +7(A -B) = 8(2000) +7(100)
10A = 16,700
A = 1670
B = 1570 . . . . 100 less than A
Dawn has $1670 in account 1 and $1570 in account 2.
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<em>Check</em>
3/8(1670) +7/8(1570) = 626.25 +1373.75 = 2000
3e-1.5f-.375 is the answer.
I think it’s d because that’s where the z would come from with the AEC right angle.