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3 years ago

What’s 2 + 2? A. 0 B. 1 C. 2 D. 4

Mathematics

2 answers:

snow_tiger [21]3 years ago

8 0

Answer:

are u kidding me it's literally D --_--

Step-by-step explanation:

Margarita [4]3 years ago

6 0

Answer is D. 4 because when u add two to two it is 4

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Find two numbers whose product is 110, and whose sum is 21.

shutvik [7]

Answer:

10 and 11

$10 \times 11 = 110$

$10 + 11 = 21$

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2 years ago

Of 200 people surveyed, 80 percent own a cellular phone and 45 percent own a pager. If all 200 people surveyed own a cellular ph

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3 years ago

If a storm window has an area of 448 square inches, what are the dimensions if the window is 12 inches higher than it is wide (w

Sholpan [36]

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28 is 12 inches higher than 16 so it should work.

5 0

4 years ago

Read 2 more answers

For a sample of n = 30 scores, a score that is 6 points above the mean has a z-score of z = 1.50. What is the sample standard de

sleet_krkn [62]

Answer:

Step-by-step explanation:

The z-score is calculated by the following formula

z=(x-μ)/σ

where

μ=Population mean

σ=Population standard deviation

If the z-score for a specific sample mean is discussed then z-score is computed as

z=xbar-μ/σxbar.

where

μ=Population mean

σxbar=Sample standard deviation

As the population mean and mean of sampling distribution of mean are equal so, μ is used in above equation.

Now, the z-score is given

1.5=xbar-μ/σxbar

σxbar=xbar-μ/1.5.

Also we know that z-score corresponds to a score that is 6 points above mean which means that xbar-μ=6.

σxbar=6/1.5

σxbar=4.

Thus, the required sample standard deviation is 4.

6 0

4 years ago

Find the absolute maximum and minimum values of f(x, y) = x+y+ p 1 − x 2 − y 2 on the quarter disc {(x, y) | x ≥ 0, y ≥ 0, x2 +

Andreas93 [3]

Answer:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

Step-by-step explanation:

In order to find the absolute max and min, we need to analyse the region inside the quarter disc and the region at the limit of the disc:

Region inside the quarter disc:

There could be Minimums and Maximums, if:

∇f(x,y)=(0,0) (gradient)

we develop:

(1-2x, 1-2y)=(0,0)

x=1/2

y=1/2

Critic point P(1/2,1/2) is inside the quarter disc.

f(P)=1/2+1/2+p1-1/4-1/4=1/2+p1

f(0,0)=p1

We see that:

f(P)>f(0,0), then P(1/2,1/2) is a maximum relative

Region at the limit of the disc:

We use the Method of Lagrange Multipliers, when we need to find a max o min from a f(x,y) subject to a constraint g(x,y); g(x,y)=K (constant). In our case the constraint are the curves of the quarter disc:

g1(x, y)=x^2+y^2=1

g2(x, y)=x=0

g3(x, y)=y=0

We can obtain the critical points (maximums and minimums) subject to the constraint by solving the system of equations:

∇f(x,y)=λ∇g(x,y) ; (gradient)

g(x,y)=K

Analyse in g2:

x=0;

1-2y=0;

y=1/2

Q(0,1/2) critical point

f(Q)=1/4+p1

We do the same reflexion as for P. Q is a maximum relative

Analyse in g3:

y=0;

1-2x=0;

x=1/2

R(1/2,0) critical point

f(R)=1/4+p1

We do the same reflexion as for P. R is a maximum relative

Analyse in g1:

(1-2x, 1-2y)=λ(2x,2y)

x^2+y^2=1

Developing:

x=1/(2λ+2)

y=1/(2λ+2)

x^2+y^2=1

So:

(1/(2λ+2))^2+(1/(2λ+2))^2=1

$\lambda_{1}=\sqrt{1/2}*-1 =-0.29$

$\lambda_{2}=-\sqrt{1/2}*-1 =-1.71$

$\lambda_{2}$ give us (x,y) values negatives, outside the region, so we do not take it in account

For $\lambda_{1}$ : S(x,y)=(0.70, 070)

and

f(S)=0.70+0.70+p1-0.70^2-0.70^2=0.42+p1

We do the same reflexion as for P. S is a maximum relative

Points limits between g1, g2 y g3

we need also to analyse the points limits between g1, g2 y g3, that means U(0,0), V(1,0), W(0,1)

f(U)=p1

f(V)=p1

f(W)=p1

We can see that this 3 points are minimums relatives.

Conclusion:

We compare all the critical points P,Q,R,S,T,U,V,W an their respective values f(x,y). We find that:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

4 0

3 years ago