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Molodets [167]
4 years ago
13

4 + 4 = plz help me question below!

Mathematics
2 answers:
STALIN [3.7K]4 years ago
5 0

Answer:

A

Step-by-step explanation:

5y=32

trying to get y by itself

y=32/5

32/5 is the same as 6 and 2/5

pls  mark me brainliest

juin [17]4 years ago
5 0
You’re trying to get the variable, y, by itself. To do that, divide by 5. What you do to one side of the equation, you do to the other. So divide 32 by 5 also which will give you 6.4 or 6 2/5. I hope this helps!! :))
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Step-by-step explanation:

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Answer:

<h2>C</h2>

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3 years ago
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

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Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
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coldgirl [10]

Answer:

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To enter he needs to pay the admission ( 10.9 ) and also each game ( x ) he plays ( 6.18 )

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3 years ago
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