Evaluate the sum or explain why it diverges: Sigma^infinity_k = 3(-3/2)^k

Mathematics

1 answer:

LenaWriter [7]2 years ago

8 0

Answer:

Step-by-step explanation:

Remember that in the geometric serie if | r | < 1 the serie converges and if | r | ≥1 the serie diverges.

I suppose that the serie starts at 0, so using the geometric serie with r = | $\frac{-3}{2}$ | > 1 the serie diverges.

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