Find three consecutive integers whose sum is six times the greater integer
1 answer:
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If you're completing the square the answer is in the image.
expression
x^2 + 5x - 5=ax^2+bx+c
a=1, b=5, c=-5, and you can solve it that way.
As, synthetic division by -4 gives remainder 0. Hence, Option B is correct. -4 is a root of
As, x+4=0 gives x=-4.
So, option C is correct,
(x+4) is factor of
Option E is correct
