Is 5 a perfect square

PLEASE HELP!!! Given the functions, f(x) = 6x + 2 and g(x) = x - 7, perform the indicated operation. When applicable, state the

Brums [2.3K]

Answer:

The domain restriction for (f/g)(x) is x=7

Step-by-step explanation:

we have

$f(x)=6x+2$

$g(x)=x-7$

so

$(f/g)(x)=\frac{6x+2}{x-7}$

Remember that

the denominator can not be equal to zero

so

Find the domain restriction

x-7=0

x=7

therefore

The domain is all real numbers except the number 7

(-∞,7)∪(7,∞)

4 0

3 years ago

Read 2 more answers

Zoya asked the students of her class their baseball scores and recorded the scores in the table shown below: Baseball Scores Sco

nlexa [21]

Answer:

4.06

Step-by-step explanation:

Given :

Scores Number of students

0 1

1 2

2 5

3 3

4 6

5 7

6 9

To Find: Mean

Solution:

Mean = $\frac{\text{Sum of all scores}}{\text{number of students}}$

Mean = $\frac{0 \times 1+1\times 2+2\times 5+3\times 3+4\times 6+5\times 7+6\times 9}{1+2+5+3+6+7+9}$

Mean = $\frac{134}{33}$

Mean = $4.06$

Hence, The Mean of baseball score is 4.06 .

4 0

3 years ago

Read 2 more answers

When you add two rational numbers, each number can be written as a?

ra1l [238]

The correct answer to your question is... a rational #, because when you add two rational #'s, each # can be written as a rational #.

Reasoning:
So, adding two rational #'s like adding fractions will result in another fraction of this same form since integers are closed under + and x. Thus, adding two rational #'s produces another rational #.

By the way # means number.

I hope this helps!
Please Rate & Thank!
Please mark as Brainliest!

Have a wonderful day! : )

8 0

3 years ago

After once again losing a football game to the college'ss arch rival, the alumni association conducted a survey to see if alumni

antoniya [11.8K]

Answer:

a) The 90% confidence interval would be given (0.561;0.719).

b) $p_v =P(z>2.8)=1-P(z$

c) Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=64 represent were in favor of firing the coach

$\hat p=\frac{64}{100}=0.64$ estimated proportion for were in favor of firing the coach

$p_o=0.5$ is the value that we want to test since the problem says majority

$\alpha$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

p= population proportion of Americans for were in favor of firing the coach

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.64 - 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.561$

$0.64 + 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.719$

And the 90% confidence interval would be given (0.561;0.719).

Part b

We need to conduct a hypothesis in order to test the claim that the proportion exceeds 50%(Majority). :

Null Hypothesis: $p \leq 0.5$

Alternative Hypothesis: $p >0.5$

We assume that the proportion follows a normal distribution.

This is a one tail upper test for the proportion of union membership.

The One-Sample Proportion Test is "used to assess whether a population proportion $\hat p$ is significantly (different,higher or less) from a hypothesized value $p_o$ ".

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

$np_o =100*0.64=64>10$

$n(1-p_o)=100*(1-0.64)=36>10$

Calculate the statistic

The statistic is calculated with the following formula:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o(1-p_o)}{n}}}$

On this case the value of $p_o=0.5$ is the value that we are testing and n = 100.

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}=2.8$

The p value for the test would be:

$p_v =P(z>2.8)=1-P(z$

Part c

Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

6 0

3 years ago

What is the intial value and rate of change in this graph. please explain step by step!!!!!

WARRIOR [948]

The initial value of the graph is where $x = 0$ . Thus, in this case, the initial value is 12.