A(0.3−y)+1.1+2.4x (y−1.2) =0 =−1.2(x−0.5)
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Answer:
Step-by-step explanation:
Hey there!
Standard form is what this equation is in
Standard form is this:
So order to complete the square, you need to take the term out of the equation, divide it by two, and then square it
In this case, the term is 8
We need to divide 8 by 2 ---> 4
Then square 4 ---> 16
So now you should add 16 to both sides
Now you can simplify the LHS
Now you subtract 16 from both sides
So this is as far as you can go since you cannot take the square root of a negative number
