1. Show your work using a Punnett square. Cross a homozygous dominant (black) rabbit with a homozygous recessive (white) rabbit.
Fur color is inherited on the autosomes. What % of the progeny will be homozygous dominant, heterozygous, and homozygous recessive? B = dominant allele, codes for black; b = recessive allele, codes for white in the homozygous condition.2. Show your work using a Punnett square. Using the trait in the above example, cross a heterozygous rabbit with a heterozygous rabbit. What % of the progeny will be homozygous dominant, heterozygous, and homozygous recessive?
2 answers:
Answer:
1. 0% will be homozygous dominant, 100% will be hetrozygous, 0 % will be homozygous recessive
2. 25% will be homozygous dominant, 50% will be hetrozygous, 25 % will be homozygous recessive
Explanation:
1. see the attachment for Punnet square
BB: homozygous(black) rabbit
bb: homzygous ( white) rabbit
2. see the attachment for Punnet square
Bb: hetrozygous(brown) rabbit
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Answer:
only females
Explanation:
In humans, sex chromosomes in males and females are different. The sex chromosomes found in humans are X and Y chromosomes. X-linked trait is a trait which is inherited on the X- chromosome. According to the question, the trait is passed on a X-linked dominant condition, which means the condition is inherited on the abnormal dominant X-chromosome that will express itself even when in an heterozygous state with a normal X-chromosome.
Hence, a father affected by the condition will have a genotype; XY while a mother that does not have the condition will have a genotype: xx (two normal x chromosomes). Since the Father can only pass his X chromosome to his daughters and never his sons, all his daughters will inherit the condition (see the punnet square in attached image).
N.B: None of the sons will inherit the condition since the mother will pass normal X-chromosomes (x) to her sons.
