Answer:
Part A: <u>Which point represents the origin? </u>
- The origin is the point with both zero coordinates: (0, 0)
Part B: <u>Starting from the origin, explain how to plot the following three points accurately (1,-1) (-1.1.25) (-2,3).</u>
Reference point is the origin for below.
- (1,-1) - go <u>right </u>by 1 unit and <u>down </u>by 1 unit, plot the point
- (-1.1.25)- go <u>left </u>by 1 unit and <u>up </u>by 1.25 or 1 and 1/4 units, plot the point
- (-2,3) - go <u>left </u>by 2 units and <u>up</u> by 3 units and plot the point
Answer:
φ ≈ 1.19029 radians (≈ 68.2°)
Step-by-step explanation:
There are simple formulas for A and φ in this conversion, but it can be instructive to see how they are derived.
We want to compare ...
y(t) = Asin(ωt +φ)
to
y(t) = Psin(ωt) +Qcos(ωt)
Using trig identities to expand the first equation, we have ...
y(t) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)
Matching coefficients with the second equation, we have ...
P = Acos(φ)
Q = Asin(φ)
The ratio of these eliminates A and gives a relation for φ:
Q/P = sin(φ)/cos(φ)
Q/P = tan(φ)
φ = arctan(Q/P) . . . . taking quadrant into account
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We can also use our equations for P and Q to find A:
P² +Q² = (Acos(φ))² +(Asin(φ))² = A²(cos(φ)² +sin(φ)²) = A²
A = √(P² +Q²)
_____
Here, we want φ.
φ = arctan(Q/P) = arctan(5/2)
φ ≈ 1.19029 . . . radians
Answer:
12
Step-by-step explanation:
The magnitude of the resulting vector, u - v, is approximately 5.83
and its angle of direction is approximately 59.04°.
<h3>How to find the magnitude of the resulting vector?</h3>
We want to subtract vector v from vector u.
We are given;
v = <2, -3> = 2i - 3j
u = <5, 2> = 5i + 2j
u - v = 5i + 2j - (2i - 3j)
= 5i + 2j - 2i + 3j
= 3i + 5j
Resultant vector = √(3² + 5²)
Resultant vector = √34 ≈ 5.83
Angle of direction of resultant vector is;
tan θ = (5/3)
θ = tan⁻¹(5/3)
θ = 59.04°
Read more about Magnitude of Vector at; brainly.com/question/3184914
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