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zepelin [54]
4 years ago
9

Evaluate f(x) = X(With an exponent of 2) -3x +2, given f(x + 1).

Mathematics
1 answer:
Lana71 [14]4 years ago
8 0

Answer:

f(x + 1) = x² - x

Step-by-step explanation:

f(x) = x² - 3x + 2 when f(x + 1)

f(x + 1) = (x + 1)² - 3(x + 1) + 2

f(x + 1) = (x² + 2x + 1) + (-3x - 3) + 2

f(x + 1) = x² - x + 0

f(x + 1) = x² - x

Best of Luck!

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Natasha2012 [34]

Answer:

<em>XY = 92 units</em>

Step-by-step explanation:

<u>Similar Shapes</u>

Two shapes are similar if all their corresponding side measures are in the same proportion.

The triangles UVW and YVX are similar because their side lengths are in the proportion 1:2, given the tick marks provided in the drawing.

This means that the measure of VX is twice the measure of VW,

The measure of YV is twice the measure of UV

The measure of XY is twice the measure of UW

This last proportion gives the equation:

z + 46 = 2z

Solving for z:

z = 46

Thus, XY = z+46 = 92

XY = 92 units

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Step-by-step explanation:

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ALGEBRA Find the value of x in each figure.<br><br> HELP ASAP
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x=17

Step-by-step explanation:

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Given that JKLM is a rhombus, find angle KJM. A. 37° C. 106° B. 74° D. 143°
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The answer in which you were looking for is C. 106 
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Question:

Identify the sets that contain 2 as an element. (Check all that apply.)

A.\ \{2, 3, 4, 5, ...\}

B.\ \{0, 1, 4, 9, ...\}

C.\ \{2, \{2\} \}

D.\ \{\{2\}, \{\{2\}\}\}

E.\ \{\{2\}, \{2, \{2\}\}\}

F.\ \{\{\{2\}\}\}

Answer:

A.\ \{2, 3, 4, 5, ...\}

C.\ \{2, \{2\} \}

Step-by-step explanation:

Required

For which of the options is 2 an element

A.\ \{2, 3, 4, 5, ...\}

The elements of this set starts from 2, then 3 and continues as thus.

Hence: 2 is an element

B.\ \{0, 1, 4, 9, ...\}

From the given elements in the above set, 2 is not listed.

Hence: 2 is not an element of this set

C.\ \{2, \{2\} \}

Here, 2 is listed as an element, 2 is also listed as a subset.

Since 2 is listed as an element, then 2 is an element of the set.

D.\ \{\{2\}, \{\{2\}\}\}

Here, 2 is listed as a subset of {2} and also as a subset of subset of {{2}}.

Since 2 is not listed as an element itself, then 2 is not an element of the set.

E.\ \{\{2\}, \{2, \{2\}\}\}

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Hence: 2 is not an element of the set

F.\ \{\{\{2\}\}\}

Here, 2 is listed as a subset of subset of {{2}}. This set only contains subsets, i.e. 2 is not listed as a direct element of the set.

Hence: 2 is not an element of the set

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3 years ago
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