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2 years ago

There's supposed to be 2 ansers for x, by the way

Mathematics

2 answers:

ololo11 [35]2 years ago

4 0

3tanx=-4
tanx=-4/3

Now

we know tan53=4/3

But it's negative

So tan is either in 2nd or 4th quadrant

For 2nd Quarter

x=π/2+53=90+53=143°

For 4th quadrant

x=3π/2+53=270+53=323°

lorasvet [3.4K]2 years ago

3 0

Answer:

x = 143° and x = 323°

Step-by-step explanation:

Solving

3tanx = -4
tanx = -4/3
tan values are negative in the 2nd and 4th quadrant
The base value is x = 53°

In Quadrant II,

90° + 53°
⇒ x = 143°

In Quadrant IV,

270° + 53°
⇒ x = 323°

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3 years ago

There's supposed to be 2 ansers for x, by the way​

There's supposed to be 2 ansers for x, by the way