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AleksAgata [21]
3 years ago
7

For fun question

Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0
Consider the function f(x)=x^{1/3}, which has derivative f'(x)=\dfrac13x^{-2/3}.

The linear approximation of f(x) for some value x within a neighborhood of x=c is given by

f(x)\approx f'(c)(x-c)+f(c)

Let c=64. Then (63.97)^{1/3} can be estimated to be

f(63.97)\approxf'(64)(63.97-64)+f(64)
\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375

Since f'(x)>0 for x>0, it follows that f(x) must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function f(x). This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...
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sveta [45]

Using the midline property;

2wy = vz

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p = 35

8 0
2 years ago
1) Which relation is a function?
jasenka [17]

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B

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2 years ago
Plz help... must show steps....will pick brainiest Solve, finding all solutions in [0,2pi)
Triss [41]
A graphing calculator shows solutions to be
.. x = {π/4, 2.034, 5π/4, 5.176}

___
Asked and answered elsewhere.
brainly.com/question/8691400

3 0
3 years ago
A triangle has side lengths of (10x + 7y) centimeters, (3x + 3z) centimeters, and (8z +10y) centimeters. Which expression repres
Kay [80]

Answer:

(D) 13x + 17y + 11z

is right answer

8 0
2 years ago
Free points !!!!!<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B1%7D%20" id="TexFormula1" title=" \sqrt[3]{1} " a
Artist 52 [7]

Answer:

hello there

your answer is <u>1</u>

Step-by-step explanation:

hope it helps....

thanks for the free points!!!

7 0
2 years ago
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