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Naddika [18.5K]
2 years ago
6

Which is NOT a correct way to describe the function {(-3, 2), (1,8), (-1, 5), (3, 11)

Mathematics
1 answer:
lora16 [44]2 years ago
5 0

Answer:

G

Step-by-step explanation:

The graph appears to have function inputs and outputs reversed. The other representations are correct.

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Klio2033 [76]

Answer:

y

Step-by-step explanation:

6 0
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Pls help fast! Will mark first correct answer as brainliest!!!
hammer [34]

Answer:

the first one is 267% and 400%

Step-by-step explanation:

but i don't know for the 2nd

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3 years ago
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How do u put 72 7/10 into decimal?
NNADVOKAT [17]

Answer:

72.7

Step-by-step explanation:

First multiply 72 by 10

because 72 is 72 10s, making it a whole number.

then add 720 (72 times 10) to 7.

then all of that over 10.

then just divide.

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Given z=4+3i evaluate z​
DerKrebs [107]

Answer:

5

Step-by-step explanation:

Assuming we want to evaluate |z|, given that, z=4+3i.

Then, by definition of modulus,

|x + yi|  =  \sqrt{ {x}^{2} +  {y}^{2}  }

|4+ 3i|  =  \sqrt{ {4}^{2} +  {3}^{2}  }

|4+ 3i|  =  \sqrt{ 16+  9 }  \\ |4+ 3i|  =  \sqrt{25 }  \\ |4+ 3i|  = 5

Therefore the modulus be of the given complex number is 5 units

5 0
3 years ago
What is the volume of the cylinder shown below?
Anastasy [175]

<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>it </em><em>is </em><em>given </em><em>that</em><em>. </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>height</em><em> </em><em>of </em><em>cylinder</em><em> </em><em>=</em><em> </em><em>1</em><em>5</em><em>u</em><em>n</em><em>i</em><em>t</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>base </em><em>=</em><em> </em><em>9</em><em>u</em><em>n</em><em>i</em><em>t</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>volume</em><em> of</em><em> </em><em>cylinder</em><em> </em><em>=</em><em> </em><em>π </em><em>r^</em><em>2</em><em>h</em><em> </em><em>cubic </em><em>unit</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>now,</em><em> </em><em>putting</em><em> the</em><em> value</em><em> of</em><em> </em><em>height</em><em> and</em><em> </em><em>radius </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>in </em><em>above </em><em>formula </em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>2</em><em>2</em><em>/</em><em>7</em><em> </em><em>*</em><em>9</em><em>*</em><em>9</em><em>*</em><em>1</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>3</em><em>6</em><em>1</em><em>7</em><em>7</em><em>c</em><em>u</em><em>b</em><em>i</em><em>c</em><em> </em><em>unit</em>

4 0
3 years ago
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