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3 years ago

Least common denominator of 6/7 and 5/14

Mathematics

1 answer:

Darya [45]3 years ago

5 0

Answer:

Step-by-step explanation:

You can‘t simplify 5/14 because 5 is a prime number. So, now you have to convert the 6/7 to 12/14 to match it up to 5/14. They now have a common denominator of 14.

Hope this helps! :)

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Britney read a total of 10 books over 2 months. After belonging to the book club for 3 months, how many books will Britney have

agasfer [191]

Answer:

she will have read 15 books in all

Step-by-step explanation:

if she has read 10 books in 2 months that means she has read 5 books each month, because 10 ÷ 2 = 5.

so if another month passes by that means she reads another 5 books.

10 + 5 = 15

so in total britney has read 15 books in total

7 0

3 years ago

What is nearest ten thousand of 63849

kodGreya [7K]

The nearest ten thousand of 63849 would be 60000

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3 years ago

Need help on #15 ..........

Rama09 [41]

Just multiply man 2*4 2*3 1.5*4 and 1.5*3.

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2 years ago

Four times the difference of 17 and a number is 84. Which equation below can be used to find the unknown number?

Xelga [282]

4(17-n)=84, 17-n means the difference between 17 and a number multi that by 4 so the answer is 4(17-n)=84

6 0

3 years ago

Rebecca has 12 photos she wants to hang side by side on her wall.A. If she only wants to display 8 of the photos, in how many wa

Mariana [72]

If she will choose 8 from 12 photos, the total number of ways she can choose is given by a combination of 12 choose 8, since the order of the photos doesn't matter.

The formula for a combination of n choose p is:

$C(n,p)=\frac{n!}{p!(n-p)!}$

For n = 12 and p = 8, we have:

$C(12,8)=\frac{12!}{8!(12-8)!_{}}=\frac{12\cdot11\cdot10\cdot9\cdot8!}{8!\cdot4!}=\frac{12\cdot11\cdot10\cdot9}{4\cdot3\cdot2}=495$

So there are 495 ways.

If she wants to arrange the 12 photos, the total number of ways is given by the factorial of 12:

$12!=12\cdot11\cdot10\cdot9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2=479001600$

There are 479,001,600 ways.

Since 10 photos already have specific places, we need to calculate the number of ways to arrange the other two photos in the two remaining places.

In this case, there are only 2 ways of organizing the remaining two photos:

Photo 1 first, photo 2 last, or photo 1 last and photo 2 first.

6 0

1 year ago