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Vika [28.1K]
3 years ago
14

1. Suppose that you have a goal to drive two miles at an average rate of 60 miles per hour (mph). During the first mile you trav

el at a rate of 30 mph. How fast would you need to travel during the second mile in order to reach your goal of 60 mph for the total two-mile distance? (Remember rate is found by taking distance divided by time.)
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0
I think about 45 mile

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Staci is attending a music festival. The ticket to the festival costs $87.96. Staci plans to purchase $30.00 t-shirt from the ev
prohojiy [21]
First, we have to calculate the remaining amount of money after the cost of the ticket. It is 200 - 87.96 = 112.04 Dividing this number to 30, we can find the maximum number of t-shirts she can buy. It is less 4 and more than 3. So that, the final answer is 3. 
4 0
3 years ago
Which of the following expressions represents the least common multiple of 15, 18, and 25?
Virty [35]

Answer:

(2)(3^2)(5^2)

Step-by-step explanation:

we know that

The <u>Least Common Multiple</u> (LCM) of a group of numbers is the smallest number that is a multiple of all the numbers.

we have

15,18 and 25

Decompose the numbers in prime factors

15=(3)(5)

18=(2)(3^2)

25=(5^2)

Multiply common and uncommon numbers with their greatest exponent

so

The LCM is equal to

LCM=(2)(3^2)(5^2)

LCM=450

7 0
3 years ago
In a binomial experiment with 45 trials, the probability of more than 25 success can be approximated by What is the probability
Pani-rosa [81]

Answer:

0.6 is the probability of success of a single trial of the experiment

Complete Problem Statement:

In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by P(Z>\frac{(25-27)}{3.29})

What is the probability of success of a single trial of this experiment?

Options:

  • 0.07
  • 0.56
  • 0.79
  • 0.6

Step-by-step explanation:

So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:

\mu =\frac{np}{\sigma}=\sqrt{np(1-p)}

now,

Z=\frac{X-\mu}{\sigma}

so,

by comparing with P(Z>\frac{(25-27)}{3.29}), we get:

μ=np=27

\sigma=\sqrt{np(1-p)} =3.29

put np=27

we get:

\sigma=\sqrt{27(1-p)} =3.29

take square on both sides:

10.8241=27-27p

27p=27-10.8241

p=0.6

Which is the probability of success of a single trial of the experiment

5 0
3 years ago
The playground of a school has areas fixed for various activities. One-fifth of the playground is used for students to sit and r
sertanlavr [38]

Answer:

2/3* 4/5 = 8/15

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  Please have a look at the attached file below.

Given:

  • One-fifth (1/5)  of the playground is used for students to sit and read
  • 2/3 is used for playing soccer
  • The rest of the playground is used for playing basketball

So assume that the the playground is divided into 5 equal part

=> 1 part is used for students to sit and read or (1/5)

=>  the remaining equal part is 4  or (4/5)

Because 2/3 of the remaining part is used for playing soccer

=> the equation represents the part of the playground used for soccer is:

2/3 of 4/5

= 2/3* 4/5

= 8/15

8 0
2 years ago
Write each expression using n as your variable.
frozen [14]
C3=n
N x 2 - 6 + 2
N < (6x8) - 10
8 0
1 year ago
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