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2 years ago

36-3-(2-2) What is the solution

Mathematics

1 answer:

Fantom [35]2 years ago

5 0

It’s 33 hope it helped:) you were right btw the other person who answered it.

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Need help with the rest of my problems

mariarad [96]

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3 years ago

Solve for X-4 1/6 = 9 1/3

Gala2k [10]

Answer:

13 1/2

Step-by-step explanation:

X-4 1/6 = 9 1/3

Add 4 1/6 to each side

X-4 1/6+ 4 1/6 = 9 1/3 + 4 1/6

x = 9 1/3 + 4 1/6

= 9 2/6 + 4 1/6

13 3/6

13 1/2

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3 years ago

Wxyz is a rectangle, what is zx

Alika [10]

ZX is a diagonal line from corner to corner.

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3 years ago

Read 2 more answers

Three consecutive integers whose sum is 363.

Alex777 [14]

Answer: 120,131,122
Your three integers are x, x+1, and x+2
x+x+1+x+2=363
3x+3=363
3x=360
x=120
x+1=121
x+2=122

7 0

3 years ago

Read 2 more answers

In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per

Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, $P_0=450,000$

Growth rate is, $r=5\%=0.05$

Final population is, $P=700,000$

A population growth is an exponential growth and is modeled by the following function:

$P=P_0(1+r)^x$

Taking log on both sides, we get:

$\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}$

Plug in all the given values and solve for 'x'.

$x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10$

So, for $x > 9.13$ , the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0

2 years ago