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Sedaia [141]
4 years ago
9

Why is the sum of two rational numbers always rational? Select from the drop-down menus to correctly complete the proof.

Mathematics
2 answers:
baherus [9]4 years ago
8 0

when adding you always get a rational number because you never go outside the bounds of reality XD

ValentinkaMS [17]4 years ago
3 0

Answer:

Step-by-step explanation:

The complete question is:

Why is the product of two rational numbers always rational? Select from the  Bold words to correctly complete the proof.

Let ab and cd represent two rational numbers. This means a, b, c, and d are (Integers or irrational numbers), and (b is not 0, d is not 0 or b and d are 0). The product of the numbers is acbd, where bd is not 0. Because integers are closed under (addition or multiplication), ​acbd ​ is the ratio of two integers, making it a rational number.

The correct paragraph would be:

Let \frac{a}{b} and \frac{c}{d} represent two rational numbers. This means a, b, c, and d are integers<u><em> </em></u><u><em>(because rational numbers are formed by integers, we could say that they are the ratio between two integers)</em></u>, and b is not 0 and d is not 0 <em><u>(b and d can't be zeros, because they are denominator, and a rational number with zero denominator is undefined or undetermined, infinite would say)</u></em>. The product of the numbers is \frac{a}{b} \times \frac{c}{d}, where bd is not 0. Because integers are closed under multiplication <em><u>(the product of two rational numbers actually is defined as the close up of two integers multiplication, numerators with numerators and denominator with denominator, and always the denominator product cannot be zero),</u></em> ​acbd ​ is the ratio of two integers, making it a rational number.

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A circle has its center at the center of a square with 26-inch sides. Using 3.14 for pi, find the area of the square not covered
AlladinOne [14]
For squrae
area=side²
perimiter=4(side)

for circle
area=pir²
circumference=2pir

side=diameter, diameter/2=radius=side/2


find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches

areanotcovered=676-530.66=145.34 square inches not coverd


ratio of perimiter to circumferece
perimiter=4*26=104
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7 0
3 years ago
Read 2 more answers
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So far, this eliminates the first proof table because in this table, the last line says "angle c and angle h are supplementary" which is not what we want to end up with. We want the last line to say "angle b and angle h are supplementary".

We can also eliminate the third proof table because of the statement "angle d and angle h are supplementary". They are only supplementary if they are both right angles. Also, the reasoning of "alternate interior angles" is false as they are corresponding angles.

The only thing left is the second proof table which is correctly argued from start to finish.

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