Question

Find the perimeter of triangle ABC, with coordinates A(-3, 0), B(0, 4), and C(3, 0).

Answer 1

The perimeter is the sum of the lengths of all sides.
Find the lengths of the sides using the distance formula:
$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ \\ A=(-3,0), B=(0,4), C=(3,0) \\ \\ |AB|=\sqrt{(0-(-3))^2+(4-0)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5 \\ \\ |AC|=\sqrt{(3-(-3))^2+(0-0)^2}=\sqrt{6^2+0^2}=\sqrt{6^2}=6 \\ \\ |BC|=\sqrt{(3-0)^2+(0-4)^2}=\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5 \\ \\ P=|AB|+|AC|+|BC|=5+6+5=16$

The answer is c. 16.

Answer 2

Answer: it is sixteen, have a nice day! :-)