<span>(1) 2x + y = 9
</span><span>(2) 8x – 2y = 6
</span>
You can eliminate the x or the y. I am going to eliminate the y
First multiply the first equation 2x + y = 9 by 2.
2x + y = 9
2(2x + y = 9)
4x +2y = 18
Now we have a new equation that we can use and we can eliminate the y from the other equation because +2y - 2y = 0. Lets do that now and solve for x.
4x +2y = 18
8x – 2y = 6
12x = 24
12x / 12 = 24 / 12
x = 2
So we found the value of x, which is 2. To find y, insert 2 into one of the original equations. I am going to use 2x + y = 9
2x + y = 9
2(2) + y = 9
4 + y = 9
-4 + 4 + y = 9 - 4
y = 9 - 4
y = 5
y = 5.
Our point is at (x, y) = (2,5)
x = 2
y = 5
Answer:
that would be nice for you to have to say about me nila rc
Answer:
ok, I looked at it lol ( it's A btw)
Step-by-step explanation:
Longer leg = x + 4
Shorter leg = x
Hypotenuse = x + 8
Using Pythagorean Theorem:
a^2 + b^2 = c^2
(x + 4)^2 + x^2 = (x + 8)^2
x^2 + 8x + 16 + x^2 = x^2 + 16x + 64
2x^2 + 8x + 16 = x^2 + 16x + 64
2x^2 +8x = x^2 + 16x + 48
2x^2 - 8x = x^2 + 48
x^2 - 8x = 48
x^2 - 8x - 48 = 0
You can complete the square from here or use the quadratic formula.
Completing the square:
x^2 - 8x = 48
x^2 - 8x + (-8/2)^2 = 48 + (-8/2)^2
x^2 - 8x + 16 = 48 + 16
(x - 4)(x - 4) = 64 or (x - 4)^2 = 64
x - 4 = +√64 OR x - 4 = -√64
x - 4 = +8 OR x - 4 = -8
x = 12 OR x = -4
However, you can't use negative 4 as a length because your length needs to be a positive.
So x will be 12.
Shorter leg: 12
Longer leg: 12 + 4
Hypotenuse: 12 + 8
5 thousands and 2 hundreds