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Sholpan [36]
3 years ago
10

40 POINTS I WILL AWARD BRAINLIEST

Mathematics
1 answer:
san4es73 [151]3 years ago
4 0

Answer:

y=x=b=a=s

Step-by-step explanation:

a=s=d=a=s=d=a

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How do i check an equation for extraneous solutions?
Marina86 [1]
Example:

\sqrt x(x+1)=0

This suggests two solutions, x=0 and x=-1.

However, upon plugging these solutions back into the equation, you get

\sqrt0(0+1)=0(1)=0

which checks out, but

\sqrt{-1}(1-1)=0

does not because \sqrt x is defined only for x\ge0 (assuming you're looking for real solutions only). So, we call x=-1 an extraneous solution, and the complete solution set (over the real numbers) is x=0.
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lbvjy [14]
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nikitadnepr [17]

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x=3

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Irina18 [472]
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