1) with the the following equation you can find the slope having two points
m = Y2-Y1/X2-X1 , A(-3,0) B(3,2)
m= 2-(0) / 3-(-3) m = 2/6 = 1/3, the correct option is C
Answer:
Remember,
and the range of g must be in the domain of f.
a)


The domain of f(g(x)) and g(f(x)) is the set of reals.
b)


The domain of f(g(x)) is the set of nonnegative reals and the domain of g(f(x)) is the set of number such that 
c)


The domain of f(g(x)) is the set of reals except the 1 and the domain of g(f(x)) is the set of reals except the 1 and -1
d)


The domain of f(g(x)) is the set of reals except 2, and the domain of g(f(x)) is the set of reals except -1.
e)


The domain of f(g(x)) is the set of nonnegative reals except -3. The domain of g(f(x)) is the set of nonnegative reals except -2.
Answer:
see below
Step-by-step explanation:
30
30 does not belong because it is not a perfect square
4: 2X2
9: 3X3
16: 4X4
25: 5X5
30: (some number not an integer) X (some number not an integer)
36: 6X6
49: 7X7
Here's our equation:

Factor out the left side
(-2x - 3) - 4 = 3/4 (-8x - 12)
Simplify
-2x - 7 = 3/4 (-8x - 12)
Factor out the right side
-2x - 7 = -6x - 9
Add 7
-2x = 6x - 2
Add 6x to isolate the variable
4x = -2
Divide by 4
x = - 1/2
Here is how I simplified both sides initially. I'll only be showing the right side because this is a LOT of typing.
Begin with 3/4 (-8x - 12)
Use rule
to multiply
3(-8x-12)/4
Factor 3(-8x-12)
(-8x - 12) = (-4 * 2x - 4 * 3)
Simplify (-4 * 2x - 4 * 3)
-3 * 4 (2x+3)
- 12 (2x + 3)
Now that we've factored 3/4 (-8x - 12), we're left with- 12 (2x + 3)/4.
12/4 =3, giving us -3(2x + 3)
Distribute and simplify, then you're done.