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tekilochka [14]
3 years ago
10

Which of these ordered pairs could not be a dilation of (8, -4)? (2, -1) (2, -2) (16, -8) (4, -2)

Mathematics
2 answers:
velikii [3]3 years ago
8 0

The answer is (2,-2). This is because when you set the x value over the y value, it does not simplify to the same ratio, and all of the others do. Take a look at my work...

mr_godi [17]3 years ago
3 0

Answer:

(2, -2)

Step-by-step explanation:

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Figure out the slope of the line that passed through each pair of points (4,-11) and (7,-8)​
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slope =  \frac{ - 8 - ( - 11)}{7 - 4}  \\

slope =  \frac{ - 8 + 11}{7 - 4}  \\

slope =  \frac{3}{3}  \\

slope = 1

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4 0
3 years ago
Anna is making 11 necklaces using 35 beads for each. How many beads (B) are needed to make all of the necklaces?
ss7ja [257]

Answer: c. b/35 =11

Step-by-step explanation:

the total beads is over beads of necklace and there’s 11 necklaces needed to make

8 0
3 years ago
Which solid figure has the following net?
tigry1 [53]
The answer is Square pyramid
4 0
2 years ago
Read 2 more answers
Please help me i dony know how to do this
Ipatiy [6.2K]
Substitute y = -2x + 4 into 7y = -14x +28

7y = -14x +28
7(-2x + 4)= -14x +28
-14x + 28 = -14x +28
0 = 0

answer
infinitely many solutions


8 0
3 years ago
Someone please help.
Alexxandr [17]

Hi there!

f(x)+f(x+1)=4f(x)

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

<u>1) f(x)</u>

We're given that  f(x)=3^x:

⇒ f(x)=3^x:

<u>2) f(x+1)</u>

Now, we must find f(x+1). To do so, add 1 to x in the original function f(x)=3^x:

⇒ f(x+1)=3^x^+^1

<u>3) 4f(x)</u>

To find 4f(x), multiply the original function f(x)=3^x by 4:

4f(x)=4*3^x:

<u>4) Put it all together</u>

Now, plug each of the three parts into the equation f(x)+f(x+1)=4f(x):

f(x)+f(x+1)=4f(x)

3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x

Factor the left side

3^x*(1+3)=4*3^x

Divide both sides by 3^x

1+3=4\\4=4

Because this equation is true, f(x)+f(x+1)=4f(x) is therefore true.

I hope this helps!

3 0
3 years ago
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