(2x+4) +(3x-1) +(x+1)=34
6x+4=34
x=5
AB=14, BC=14, AC=6
So just use a calculator but here goes
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
3^6=729
and 3^7 is 2187 which is excluded
Actually, no they cannot. The midpoint is the single point at the very center of the line segment. Since no segment can have multiple centers, they cannot have more than a single midpoint. Sorry :3
Hope this helped!! :D
