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Alex17521 [72]
4 years ago
7

Find the x-coordinates where f '(x) = 0 for f(x) = 2x + sin(2x) in the interval [0, 2π]. so far I found f'(x)=2cos(2x)+2 cos(2x)

=-1
Mathematics
2 answers:
rusak2 [61]4 years ago
6 0
From there, you simply need algebra and a calculator that works in radians.

Take the inverse cos of both sides to get 2x = arccos(-1) 

Then divide both sides by 2 to get x = arccos(-1) / 2 

Put that into a calculator and you get π/2. But because your bounds are 0 to 2π, you have to add π your solution to get the solution on the other side of the unit circle, which would be (3π/2).

Now that you have the x value, put (π/2) and (3π/2) into f(x) to get the y coordinate. 

f(π/2) = 2(π/2) + sin(2(π/2) = π, which means this solution is just (π/2, π)
f(3π/2 = 2(3π/2) + sin(2(3π/2) = 3π, which means this solution is (3π/2, 3π)
Katarina [22]4 years ago
3 0

The solutions of the equation f\left( x \right) = 2x + \sin \left( {2x} \right) in the interval \left[ {0,2\pi } \right] are \boxed{\left( {\frac{\pi }{2},\pi } \right)} and \boxed{\left( {\frac{{3\pi }}{2},3\pi } \right)}.

Further explanation:

Given:

The function is f\left( x \right) = 2x + \sin \left( {2x} \right).

The first derivative is zero.

Explanation:

The given function is f\left( x \right) = 2x + \sin \left( {2x} \right).

Differentiate the function with respect to x.

\begin{aligned}f'\left( x \right) &= 2 + 2\cos \left( {2x} \right)\\&= 2\left( {1 + \cos 2x} \right)\\\end{aligned}

Substitute 0 for f'\left( x \right).

\begin{aligned}2\left( {1 + \cos 2x} \right) &= 0 \\1 + \cos 2x &= 0\\\cos 2x &= - 1\\2x &= {\cos ^{ - 1}}\left( { - 1} \right)\\2x &= \frac{{\left( {2n - 1} \right)\pi }}{2} \\\end{aligned}

In the interval \left[ {0,2\pi } \right] the x-coordinates are \boxed{\frac{\pi }{2}}{\text{ and }}\boxed{\frac{{3\pi }}{2}}.

The solutions of the equation f\left( x \right) = 2x + \sin \left( {2x} \right) in the interval \left[ {0,2\pi } \right] are \boxed{\left( {\frac{\pi }{2},\pi } \right)} and \boxed{\left( {\frac{{3\pi }}{2},3\pi } \right)}.

Learn more:

  1. Learn more about inverse of the function brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Application of derivatives

Keywords: derivative, x – coordinates, interval, far, 2x, sin2x, coordinates, 0, 2pi, y-coordinate.

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