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STALIN [3.7K]
3 years ago
5

How do you estimate a whole number 3,576

Mathematics
2 answers:
slava [35]3 years ago
6 0
- - To estimate a whole number you need to divide it by the same number that equals it.
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frozen [14]3 years ago
5 0
By dividing it by a number that = to it
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The temperature at 7:00 a.m. was 8•F. By noon, the temperature had risen 6 degrees
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At noon the temperature is 14° F

Step-by-step explanation:

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F(x)= \frac{ \sqrt{x-6} }{ \sqrt{x-4}
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Hi!

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A=1/2bh. A=200ft. H=10. What is b
Svetllana [295]

Answer:

B= \frac{2A}{H}

Step-by-step explanation:

If you noticed, A= \frac{1}{2}BH is the formula for finding the area for a triangle. Your goal is to get B by it's self. Your first step will be to clear of the fraction first, so you will multiply both sides by 2.   2(A)=2(\frac{1}{2}BH).    On the left, you have 2×A= On the right side, you have     2(\frac{1}{2}BH),     but since you have a number in the equation, you will only use 2×\frac{1}{2}. To solve  2×\frac{1}{2}, you will cnacel out both 2's and you have 1. 1×BH will still equal BH, so you are now left will B×H.

(Your new equation looks like this by the way).    2A=BH

Since you need to get B by its self, the way to clear the H away from the B is by dividing.  You will now divide the B and H aswell as 2A and H. (It will look like this) \frac{2A}{H} = \frac{BxH}{H} . (Again when you have the same number or letter, you cross it out. When you divide, you won't change anything on the left side, and all you have to do on the right id to cross out the H next to the B and cross out the H on the bottom of the equation). You should be left with \frac{2A}{H} = B. Now you can turn it around for your final answer. B= \frac{2A}{H}.

Please let me know if i helped, how I did, and if you have any questions.

3 0
3 years ago
ABC​ Designs, which produces​ rings, is developing direct material standards. Each ring requires 0.52 kilograms of a special met
Maru [420]

The standard quantity of metal per​ ring is 0.57 kilograms.

Step-by-step explanation:

Each ring requires 0.52 kilograms of a special metal.

The allowance for waste is 0.03 kilograms per​ ring, while the allowance for rejects is 0.02 kilograms per ring.

So, the standard quantity of metal per​ ring = 0.52 kg of metal required + 0.03 kg of allowance for waste + 0.02 kg of allowance for rejects)

= 0.52+0.03+0.02=0.57 kilograms.

Hence,  the standard quantity of metal per​ ring is 0.57 kilograms.

7 0
4 years ago
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