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2 years ago

Omar's gas tank is 1/10 full. After he buys 6 gallons of gas, it is 2/5 full. How many gallons can Omar's tank hold?

1 answer:

4 0

1/10x + 6 = 2/5x
6 = 2/5x - 1/10x
6 = 4/10x - 1/10x
6 = 3/10x
6 / (3/10) = x
6 * 10/3 = x
60/3 = x
20 = x <=== the gas tank can hold 20 gallons

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What is the equation for the line in the slope intercept form enter your answer in the box

Hoochie [10]

Answer:

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Step-by-step explanation:

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2 years ago

A clothing store spends $10 for each shirt it produces and has fixed costs of $400. If the store makes 50 shirts, how much shoul

Kazeer [188]

Answer:

b)$18

Step-by-step explanation:

The break even point is when the revenue is equal to the cost.

Revenue:

How much the store earns for each shirt.

We want to find the price of each shirt, and 50 shirts will be made.

So the revenue function is:

$R = 50p$

In which p is the price.

Costs:

A clothing store spends $10 for each shirt it produces and has fixed costs of $400.

So for 50 shirts:

400 + 50*10 = 900

Breakeven

Revenue equals cost

50p = 900

p = 900/50

p = 18

So the correct answer is:

b)$18

8 0

3 years ago

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

3 years ago

Matthew haa 18 sets of baseball cards each st has 12 cards about how many baseball card does matthew have

cluponka [151]

18 x 12 = 216

216 baseball cards

6 0

2 years ago

What is the unit rate for 15 apples eaten in 5 minutes for 15 apples eaten in 5 minutes

USPshnik [31]

The unit rate is 3 apples per minute

Step-by-step explanation:

Unit rate will be calculated by dividing the total number of apples by the time

Given

Total number of apples = 15

Time = 5 min

So, The unit rate will be:

$Unit\ rate=\frac{Apples}{Time}\\=\frac{15}{5}\\=3\ apples\ per\ min$

Hence,

The unit rate is 3 apples per minute

Keywords: Unit rate, Division

Learn more about unit rate at:

#LearnwithBrainly

8 0

2 years ago