For number 6 I know the answer is 34 beacuse you add 6, 13, and 15 together to get 34.
(12z^2 + 25z + 12)/(3z^2 - 2z - 8)
You have to factor it. You know how to factor it right?
(12z^2 + 16z + 9z + 12)/(3z^2 - 6z + 4z - 8)
(4z(3z + 4) + 3(3z + 4))/(3z(z - 2) + 4(z - 2))
((4z + 3)(3z + 4))/((3z + 4)(z - 2))
(4z + 3)/(z - 2)
Notice that a can is a cylinder, which is basically two circles and one rectangle. Now, the question wants area of this rectangle.
You know the width of the rectangle (or the paper), which is 11cm. How do you find the length then?
Notice that the length of the rectangle is also the circumference of the circles. From here, use C = πd where C is circumference and d is diameter. The d is given, which is 7.5 cm. Depending on the question, π can be 3.14, 22/7 or the actual pi.
multiply π and 7.5cm and you get the circumference. Multiply this to 11cm and you get area of the rectangle.
Answer:
Step-by-step explanation:
t + u = 11 ----------- (1 )
10t + u = 10u + t - 9
10t + u - 10u - t = -9
10t - t + u - 10u = - 9
Combine like terms
9t - 9u = -9
Divide the entire equation by 9
t - u = -1 --------------(2)
Add equation (1) & (2) and so, u will be eliminated and we can find the value of t
(1) t + u = 11
(2) <u>t - u = -1</u>
2t = 10
t = 10/2
t = 5
Plugin t = 5 in equation (1)
5 + u = 11
u = 11 - 5
u = 6
The original number is 56
