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PSYCHO15rus [73]
3 years ago
6

Which factor can increase solubility?

Chemistry
1 answer:
alisha [4.7K]3 years ago
7 0
Solubility is the maximum amount of a substance that will dissolve in a givenamount of solvent at a specifictemperature. There are two direct factors that affect solubility:temperature and pressure.Temperature affects the solubility of both solids and gases, but pressureonly affects the solubility of gases.Jul 12, 2012 More info at https://www.google.com/url?sa=t&source=web&rct=j&url=http://www.ck12.org/user:krogers/section/Factors-Affecting-Solubility/&ved=0ahUKEwjrhrbkgaLSAhWBTSYKHf2_CwgQFggdMAE&usg=AFQjCNEpdOlW5dWQ1GlXoJu_ufz-FhKJAQ&sig2=tPbfrbEnhCcyUiSCkWaH7w
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What sequence of DNA bases bond with the DNA base sequence ATGT
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Answer:

DNA bases bonds with each other in this sequence

Explanation:

Guanine bonds triple  bonds with cytosine respectively while Adenine bonds double bond with thymine .

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3 years ago
Which best describes the trends in electronegativity on the periodic table?
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Answer:

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Explanation:

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3 years ago
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One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was 20.826 C, and the temperature af
Licemer1 [7]

Answer:

fH = - 3,255.7 kJ/mol

Explanation:

Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.

Qsystem + Qcombustion = 0

Qsystem = heat capacity*ΔT

10000*(25.000 - 20.826) + Qc = 0

Qcombustion = - 41,740 J = - 41.74 kJ

So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:

n = mass/molar mass = 1/ 78

n = 0.01282 mol

fH = -41.74/0.01282

fH = - 3,255.7 kJ/mol

4 0
4 years ago
Calculate average kinetic energy of one mole of gas at 517K
Gekata [30.6K]

In an ideal gas, there are no attractive forces between the gas molecules, and there is no rotation or vibration within the molecules. The kinetic energy of the translational motion of an ideal gas depends on its temperature. The formula for the kinetic energy of a gas defines the average kinetic energy per molecule. The kinetic energy is measured in Joules (J), and the temperature is measured in Kelvin (K).

K = average kinetic energy per molecule of gas (J)

kB = Boltzmann's constant ()

T = temperature (k)

Kinetic Energy of Gas Formula Questions:

1) Standard Temperature is defined to be . What is the average translational kinetic energy of a single molecule of an ideal gas at Standard Temperature?

Answer: The average translational kinetic energy of a molecule of an ideal gas can be found using the formula:

The average translational kinetic energy of a single molecule of an ideal gas is  (Joules).

2) One mole (mol) of any substance consists of  molecules (Avogadro's number). What is the translational kinetic energy of  of an ideal gas at ?

Answer: The translational kinetic energy of  of an ideal gas can be found by multiplying the formula for the average translational kinetic energy by the number of molecules in the sample. The number of molecules is  times Avogadro's number:

7 0
3 years ago
Please help me with this question!<br> Am I right?
muminat
You are right!! Good job!!!
5 0
3 years ago
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