Answer:
Si₁₄ = 1s² 2s² 2p⁶ 3s² 3p²
Explanation:
Silicon is present in group 14 of periodic table.
It is blue-gray color metalloid.
Its atomic mass is 28 g/mol.
It is mostly used to make allow.
The most important alloy are Al-Si and Fe-Si. These are used to make different machine tools, transformer plates, engine etc.
Its atomic number is 14 and electronic configuration can be written as,
Electronic configuration:
Si₁₄ = 1s² 2s² 2p⁶ 3s² 3p²
The noble gas electronic configuration or abbreviated electronic configuration can also be written.
Si₁₄ = [Ne] 3s² 3p²
The atomic number of neon is 10. Its electronic configuration is,
Ne₁₀ = 1s² 2s² 2p⁶
That's why we write [Ne] for 1s² 2s² 2p⁶ in abbreviated electronic configuration of Si.
Endocrine system im pretty sure
Answer:
C) Ionic bonds
Explanation:
The ionic bonds are the strongest bond, it occurs when a metal donates electrons and a nonmetal gain these electrons. They'll be together by electrostatic force.
Metallic bonds it the second strongest bond, it occurs between metals, which loses electrons. It's an electrostatic force, but weaker than the ionic compound because it occurs between the cation and the electron.
Covalent bonds are the weakest bond. It happens between metals and nonmetals, or nonmetals and hydrogen or between atoms of hydrogen. The force that joins the atoms depends on the polarity of the molecule. Polar molecules have dipole forces, nonpolar molecules, induced dipole forces. Also, hydrogen makes special dipole forces with nitrogen, oxygen, and fluorine, called hydrogen bond.
As the stronger is the force, as difficult it will be to break it. So, ionic bonds will demand more energy to become gas, and have high melting points.
Answer:
The sum of the molar masses of each isotope of the element.
Answer:
0.03g/mL
Explanation:
Given parameters include:
Five μL of a 10-to-1 dilution of a sample; This implies the Volume of dilute sample is given as 5 μL
Dilution factor = 10-to-1
The absorbance at 595 nm was 0.78
Mass of the diluted sample = 0.015 mg
We need to first determine the concentration of the diluted sample which is required in calculating the protein concentration of the original solution.
So, to determine the concentration of the diluted sample, we have:
concentration of diluted sample = 
= 
(where ∝ was use in place of μ in the expressed fraction)
= 0.003 mg/μL
The dilution of the sample is from 10-to-1 indicating that the original concentration is ten times higher; as such the protein concentration of the original solution can be calculated as:
protein concentration of the original solution = 10 × concentration of the diluted sample.
= 10 × 0.003 mg/μL
= 0.03 mg/μL
= 0.03g/mL
Hence, the protein concentration of the original solution is known to be 0.03g/mL
