Can i get help please and thank you

Mathematics

2 answers:

lara [203]3 years ago

7 0

I think its number 3 for sure

blagie [28]3 years ago

4 0

The answer is 2.

90 would be the monthly service charge because it is being multiplied by a variable and a monthly charge means that a number is being multiplied every number of months (x). 40 would be the one time installation fee because it is only added once (because there's no variable multiplying it repeatedly.) Y is the total because the installation fee and monthly charge are combined to equal some number (y).

You might be interested in

In a survey of 2,800 people who owned a certain type of car, 1,680 said they would buy that type of car again. What percent of

Paraphin [41]

Answer:

60% were satified and would buy the car again

Step-by-step explanation:

5 0

3 years ago

A line with slope 3 passes through the point (0,10). What is the y-coordinate of the point on the line with x-coordinate 2?

lana [24]

Hello!

So to find the y-coordinate we need an equation for the line. The equation we can use is

y = mx + b

In this we already know m(the slope which is 3) and we can find b by plugging in the points that are given.

10 = 3(0) + b
10 = 0 + b
10 = b

So now that we've found b, we can use this in our equation

y = 4x + b

So now we can plug in the x-coordinate that we know (2) and find the y - coordinate.

y = 4(2) + 10
y = 8 + 10
y = 18

18 is your y-coordinate

4 0

3 years ago

How many FIVES are equal in value to £7?

OLga [1]

£1 equals to 1.43 us dollars.

7 × 1.43 = 10.01

10.01 ÷ 5 = 2.002

2 fives are equal to £7.

5 0

3 years ago

If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.

Pie

Given that $f^{(n)}(0)=(n+1)!$ , we have for $f(x)$ the Taylor series expansion about 0 as

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n$

Replace $n+1$ with $n$ , so that the series is equivalent to

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}$

and notice that

$\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}$

Recall that for $|x|$ , we have

$\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}$

which means

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}$
$\implies f(x)=\dfrac1{(1-x)^2}$

5 0

3 years ago

The temperature in minneapolis changed from -7 degrees at 6 am to 7 degrees Fahrenheit at noon. How much did the temperature inc

kotegsom [21]

It increased 14 degrees Fahrenheit

5 0

3 years ago