Answer:- Major property of a good hash code is that objects which are equal should return the same hash code .
Explanation: Hash codes is a numeric value which is used for identify a object while a equality testing .Hash code can occupy the value of any length and then returns a fixed length value. The value of hash codes are variable.
If two objects are equal then by the method of equal(object) if the hashcode() function is called on both the objects , they produce the same value.
```
#!/usr/local/bin/python3
foo = float( input( "Enter a number: " ) )
if( foo < 0.0 ):
print( "negative" )
elif( foo > 0.0 ):
print( "positive" )
else
print( "zero" )
exit( 0 )
```
First brock has to make sure he has all the hiking gear, like a camel back, gloves, the right pair of shoes. and then if he wants to take pictures he should buy a go-pro so he doesn't really have to move will the go-pro will record or take pictures.
hope i helped 0-0 ;p
plz mark brainly
Answer:
- def check_subset(l1, l2):
- status = False
- count = 0
- if(len(l1) > len(l2)):
- for x in l2:
- for y in l1:
- if x == y:
- count += 1
-
- if(count == len(l2)):
- return True
- else:
- return False
-
- else:
- for x in l1:
- for y in l2:
- if x==y:
- count += 1
-
- if(count == len(l1)):
- return True
- else:
- return False
-
- print(check_subset([1,4,6], [1,2,3,4,5,6]))
- print(check_subset([2,5,7,9,8], [7,8]))
- print(check_subset([1, 5, 7], [1,4,6,78,12]))
Explanation:
The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.
Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6). If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.
The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)
If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:
True
True
False
Answer:
b) void xyzfunc (int &myint);
Explanation:
To use the same memory location as the variable in the calling function we have to pass the variable by reference means passing the same address to the function.So to do that we have use & operator which stands for address.
We will do this as following:-
void xyzfunc (int * myint);
Hence the answer is option b.
