Answer:
64
Explanation:
We have given the 32 bit architecture
We know that 1 byte =8 bit
So memory of given architecture 32 bit 
Total memory = 256 bytes
So total number of instruction that fit into 256 bytes 
So total 64 instruction can be fit in 256 byte memory.
Answer:
C++ Code:
void sort3(double &a, double &b, double &c)
{
if(a > b)
swapdoubles(a,b);
if (b > c)
swapdoubles(b,c);
if (a > b)
swapdoubles(a,b);
}
Explanation:
To change the values of a,b,c within the function, we pass the values by reference. Let us assume that number a = 3.14, b = 2.71, c = 3.04. Since a > b, values of a and b will be swapped.Now a = 2.71 and b = 3.14. Similariy, since b > c, they will be swapped. This way, we move the largest number to its correct position in the first two steps. If there are only three numbers, and the largest number is in its correct position, then for the two remaining numbers, we will only need atmost one swap to exchange their positions. hence, we perform a comparison of a > b once again to see if the b is smaller than a. if its not, then all a,b,c are in sorted order.
i = 0
while True:
word = input("Please enter the next word: ")
if word == "STOP":
break
i += 1
print("#"+str(i)+": You entered "+word)
print("All done. "+str(i)+" words entered.")
I hope this helps!
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